THE VOLUME OF A CONE IS 15 PI CUBIC METERS. WHAT IS THE VOLUME OF A CYLINDER HAVING THE SAME BASE AND SAME HEIGHT?

Answers

Answer 1

Answer: Okay, so I know that you either multiply the volume of a cone by 3 to get the cylinders volume, or you divide it. I think you multiply it. Just remember, the rule is to multiply the volume of a cone by 3, to get the cylinder volume with the same measurements. So 15 x 3.

Answer 2

Answer:

Final answer:

To find the volume of a cone and a cylinder with the same base and height, use the formulas for volume of a cone and volume of a cylinder. Solve for r^2 * h in the cone's volume formula, then use this value in the cylinder's volume formula.

Explanation:

To find the volume of the cylinder with the same base and height as the given cone, we need to know the formula for the volume of a cone and the formula for the volume of a cylinder. The volume of a cone is given by the formula V = 1/3 * π * r^2 * h, where r is the radius of the base and h is the height of the cone. Since the cone has a volume of 15π cubic meters, we can set up the equation 15π = 1/3 * π * r^2 * h and solve for r^2 * h. Once we have r^2 * h, we can use the formula for the volume of a cylinder, V = π * r^2 * h, to calculate the volume of the cylinder.

, let's solve the equation 15π = 1/3 * π * r^2 * h for r^2 * h:

15π = 1/3 * π * r^2 * h

Multiplying both sides of the equation by 3, we get:

45π = π * r^2 * h

Canceling out the π on both sides of the equation, we get:

45 = r^2 * h

Now we have r^2 * h, which is 45. Let's plug this value into the formula for the volume of a cylinder, V = π * r^2 * h:

V = π * 45

So the volume of the cylinder with the same base and height as the given cone is 45π cubic meters.

Learn more about Volume of Cone and Cylinder here:

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Which angle forms a vertical pair with nsm a.osl b.smn c.snm d.osn

Answers

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that ∠NSM,

we need to find is vertical angles of ∠NSM,

1) ∠OSL is a vertical angle of ∠NSM as it has one common vertex and all other are collinear points.

2) ∠SMN can't be vertical angle as vertical angles must be equal at common vertex but it does not do that it forms angle on M rather than on S.

3) ∠SNM can't be vertical angles as vertical angles must be equal at common vertex but it does not do that it forms angle on N rather than on S.

4) ∠OSN can't be vertical angle as vertical angles must have only one common vertex but in this case it has two common vertex i.e. S and N. so it will be linear pair.

Hence, Option 'a' is correct.

Solve (if you can (ha ha ha)).

$x^7-128=0$

Answers

Step 1: Add 128 to both sides.
x^7−128+128=0+128
x^7=128
Step 2: Take root.x=(128)^(1/7)
x=2
Answer:
x=2

x^7 -128= 0
⇒ x^7 -2^7= 0 (because 2^7= 128)
⇒ x^7= 2^7
⇒ x= 2

The final answer is x=2~

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