Answer: Option (d) is the correct answer.
Explanation:
Atomic number of argon is 18 and its electronic configuration is .
Also, it is known that number of electrons in K, L and M shells of argon are 2, 8, 8.
Thus, we can conclude that an atom of argon in the ground state tends not to bond with an atom of a different element because the argon atom has a total of eight valence electrons.
So, as per the octet rule, last sub-shell of argon is completely filled. Hence, it will not form any bond with any other atom.
(2) The bonds between the atoms in a CH4 molecule are ionic.
(3) The geometric shape of a CH4 molecule distributes the charges symmetrically.
(4) The geometric shape of a CH4 molecule distributes the charges asymmetrically.
The following statement explains why a molecule of is nonpolar:
.
Further explanation:
Covalent Bond
This type of bonding takes place when the bonded atoms mutually share electron pairs between them. It is also called the molecule bond. The chemical compounds formed as a result of this bond are called chemical compounds.
The polarity of any bond is primarily governed by two factors; electronegativity difference and symmetry. A bond is said to be polar if the bonded atoms have a considerable molecular bondelectronegativity difference between them. But if there is very small or no electronegativity difference between the bonded atoms, the resulting bond is nonpolar in nature.
Symmetry is another factor responsible for the polarity of the bond. The charge distribution is symmetrical in case symmetry is present in the molecule and as a result, the molecule is said to be nonpolar. But if there is asymmetry in the shape of the molecule, it will be polar in nature.
The electronegativity difference between carbon and hydrogen atoms in molecule is very small or negligible so the bonds between the atoms in are nonpolar in nature. But the hydrogen atoms are placed in symmetrical positions with respect to the central carbon atom, imparting symmetry to molecule and therefore it is nonpolar (For structure, refer to the attached image).
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Answer details:
Grade: High School
Chapter: Ionic and covalent compounds
Subject: Chemistry
Keywords: covalent bond, covalent compounds, CH4, carbon, hydrogen, symmetry, electronegativity difference, nonpolar.
b. 2
c. 3
d. 4
Copper (II)iodide
Tin(IV) nitride
Choro minim (II)bromide
Iron(III)phosphide
Compounds are classified as binary or ternary based on the number of elements present in the compound. The chemical formulas for the given compounds include nickel(III)oxide, copper(II)iodide, tin(IV)nitride, chloro minimium(II)bromide, and iron(III)phosphide.
In order to identify whether a compound is binary or ternary, we need to analyze its chemical formula. Binary compounds consist of two elements, while ternary compounds consist of three or more elements. The chemical formula for each compound is as follows:
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true or false inside a nuclear power plant nuclear fission takes place within the heat exchanger
The cation radii become larger across the period.
Atomic radii increase slightly and then start to decrease.
Atomic radii decrease slightly and then start to increase.
The correct option is D.
Transition metals are those metallic elements that are located in the central block of the periodic table. They exhibit various valency states and they generally have various colors. The atomic radius of an element refers to the measure of the size of its atom. For transition metals, their atomic radii decrease slightly and then start to increase, when one is moving from the left to the right of the periodic table.
Answer : The correct option is, Atomic radii decrease slightly and then start to increase.
Explanation :
Transition metals : It is defined as the element whose atom is ground state or ion in one of the common oxidation states, has incomplete d-subshell.
The general trend of atomic radii of transition metals is :
Generally the atomic radii of d-block elements in a series decreases with increase in atomic number but decreases in atomic size is small after midway that means almost remains same and at the end of the period there is a slight increase in the atomic radii.
Hence, the atomic radii decrease slightly and then start to increase of the transition metals when moving from left to right on the periodic table.