Answer:
45
Explanation:
There are 12 Carbons
There are 22 Hydrogens
There are 11 Oxygens.
I think the answer is either 0 or 45. But the wording is very sloppy. It is not really atoms that are present. There are ions.
Go with 45 but hold your nose when writing your answer.
Answer:
Explanation:
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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2
The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2
Question
Asked Oct 30, 2019
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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.
Cl2 ⇌ 2Cl (fast, reversible)
Cl + CHCl3 → HCl + CCl3 (slow)
Cl + CCl3 → CCl4 (fast)
What rate law does this mechanism predict?
A)k G) [CHCl3]1/2 M) [CCl3]2
B) [Cl2] H) [CCl3]1/2 N) [HCl]2
C) [Cl] I) [HCl]1/2 O) [Cl2]2
D) [CHCl3] J) [Cl2]1/2 P) [Cl]2
E) [CCl3] K) [Cl]1/2
F) [HCl] L) [CHCl3]2
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Expert Answer
Step 1
The three step mechanism of the given reaction is,
CL2 dissociate to give chorine a fast and reverse reaction.
React with CHCL3 to give HCL and CCL3 a slow reaction
React with CL to give CCL4.
Step 2
Add equation (1), (2), and (3) to get the overall reaction.
The overall reaction is expressed as,
CL2 dissociate to give chorine a fast and reverse reaction.
React with CHCL3 to give HCL and CCL3 a slow reaction
React with CL to give CCL4.
Step 3
The chlorine atom produced in equation (1) is consumed in equation (3) and CCl3 a molecule is produced in equation (2) is consumed in equation (3).
CL react with CHCL3 to give a reversible reaction of HCL and CCL4.
of carbon is present in 4.00 g of butane.
Further Explanation:
The number of atoms or molecules that can be present in one mole of any substance is determined by a number, known as Avogadro’s number. The numerical value of Avogadro’s number is . Such units can either be atoms or molecules.
The formula to calculate the moles of is as follows:
…… (1)
The given mass of butane is 4.00 g.
The molar mass of butane is
Incorporate these values in equation (1).
The number of molecules present in one mole of butane is . So the expression to calculate the number of molecules of butane is as follows:
…… (2)
The number of moles of butane is 0.0688 mol.
The value of Avogadro’s number is .
Incorporate these values in equation (2).
A molecule of butane consists of four carbon atoms in it. So the number of carbon atoms can be calculated as follows:
Learn more:
Answer details:
Grade: Senior School
Chapter: Mole concept
Subject: Chemistry
Keywords: butane, C4H10, Avogadro’s number, C atoms, moles, one mole, chemical formula, carbon atoms, molar mass of C4H10, given mass of C4H10.
States of matter is useful in life because without solids we would have no cups shoes or tables and without liquids we wont be able to survive because we need water aka LIQUID to survive and without gases we wouldnt be able to breathe.