Answer:
y=8*4^x
Step-by-step explanation:
Let the exponential function be of the form y=A*B^x
We want to find constant A and B.
So I'm going to use (1,32) giving me 32=A*B
I'm going to use (4,2048) giving me 2048=A*B^4
2048/32=64
A*B^4/A*B=B^3
So If you divide the equation 2048=A*B^4 by 32=A*B
we get 64=B^3
which gives us B=4
Since 32=A*B and B=4 then A=8
So the answer is y=8*4^x
The numbers by writing and solving a system of equations are 50 and 105
Let the unknown numbers be x and y
If twice a number plus twice a second number is 310, then;
2x + 2y = 310
x + y = 155
x = 155 - y
Also, If the difference of the numbers is 55, hence;
x - y = 55
155 - y - y = 55
155 - 2y = 55
-2y = 55 - 505
2y = 100
y = 50
Substitute y = 25 into 1 to have:
x = 155 - 50
x = 105
Hence the numbers by writing and solving a system of equations are 50 and 105
Learn more on system of equations here: brainly.com/question/847634