a geologist had two rocks on a scale that weighed 2 1/2 pounds together rock A weighed a total of 1/7 of the weight how much did rock A weigh
Answers
Answer:
Let A and B be the two rocks.
As per the statement: a geologist had two rocks on a scale that weighed 2 1/2 pounds together rock
⇒Total weight of rock () =
pounds
or
Also, it is given A weighed a total of of the weight.
⇒
then;
Therefore, pounds did rock A weight.
Now
Total weight of the two rocks = 2 1/2 pounds
= 5/2 pounds
Then
Weight of Rock A = (5/2)/(1/7) pounds
= (5 * 7)/2 pounds
= 35/2 pounds
17 1/2 pounds
So Rock A weighs 17 1/2 pounds. This is the weight of Rock A and it is only required for this question. If you are eager to find the weight of rock B then you have to subtract the weight of Rock A form the total weight of the two rocks.
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Answers
x/2 + x + x/3 = 8
Simplify both sides of the equation
x/2 + x +x/3 = 8
Simplify
11/6 x = 8
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-7(x-1)-3(x-4)
Distribute
(-7)(x)+(-7)(-1)+(-3)(x)+(-3)(-4)
= -7x+7+ -3x +12
Combine like terms
-7x+7+ -3x+12
= (-7x+ -3x ) + ( 7+12)
= -10x + 19
3(x-2)^2 -5(x-2)+3
Distribute
= 3x^2 + -12x+12+(-5)(x)+(-5)(-2)+3
= 3x^2 +-12x+12+ -5x +10 +3
Combine like terms
3x^2 + -12x+12+ - 5x+10 +3
(3x^2) + (-12x+ -5x ) + (12+10+3)
= 3x^2 + -17x + 25
= 3x^2 -17x+25
I hope that's help ! Please if you have question about all 3 just let me know .