Cu(OH)2 + HCl =
H2SO4 =
HNO3 =
Why would this treatment raise the pH of the blood? Can you please explain it?
When a person has acidosis, their blood is too acidic. Sodium bicarbonate, an alkali, can help by producing hydroxide ions that neutralize excess hydrogen ions, which are responsible for the acidity. This action decreases the acidity of the blood, thereby raising its pH.
The human body's pH level is crucial to maintaining good health. When a person has acidosis, the blood is too acidic, and the pH is often less than the normal range of 7.35 to 7.45. Sodium bicarbonate, a type of alkali, can help treat this condition.
Alkalis such as sodium bicarbonate are basic compounds. When they dissolve in water, they produce hydroxide ions (OH-). These ions can neutralize the excess hydrogen ions (H+) in our body, which are responsible for creating an acidic environment. As a result of this neutralization, the amount of H+ in the body decreases, thus leading to an increase in blood pH, making it less acidic (more alkaline).
So, to put it in simpler terms, the sodium bicarbonate raises the blood's pH by reducing the amount of acid in it - making the blood less acidic and more alkaline.
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The particles in a solid are farther apart than the particles in a liquid.
The particles in a solid are closer together than the particles in a liquid.
The arrangement of a solid's and a liquid's particles will depend on the mass of the substance.
The length measurement in kilometers will be -
92.25 x 10⁻³ Kilometers.
We have length measurement of 92.25 m.
We have to determine the number of kilometers in this much length.
In 1 km there are 1000m
According to the question -
Length measurement = L = 1 meter
In kilometers, the length will be = 1 /1000 x 92.25 =
92.25 x 10⁻³ Kilometers.
Therefore, the length measurement in kilometers will be -
92.25 x 10⁻³ Kilometers.
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The answer is: 3) 7.64 days.
The most stable isotope of radon (Rn) is radon-222 with a half-life of 3.82 days.
After first half life (3.82 days) = 0.5 · 200 g.
After first half life (3.82 days) = 100 g of radon-222.
After second half life (7.64 days) = 0.5 · 100 g.
After second half life (7.64 days) = 50 g of radon-222.
Half-life is the time required for a quantity (in this example number of radioactive nuclei of radon-222) to reduce to half its initial value and is independent of initial concentration.