The potential difference between the center of the sphere and the surface of the sphere will be PD=3.6 x 10^8 V
It is given that:-
Charge Q = +4.00 mC or
insulating sphereradius R = 5.00 cm = 0.05 m
The formula for the potentialdifference at the surface of the sphere is given by
The formula for the potentialdifference at the center of the sphere
The difference between the potential difference will be
Thus the potential difference between the center of the sphere and the surface of the sphere will be PD=3.6 x 10^8 V
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Answer:
3.6 x 10^8 V
Explanation:
Q = 4 m C = 4 x 10^-3 C
r = 5 cm = 0.05 m
The formula for the potential at the surface is
Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V
The formula for the potential at the centre is
Vc = 3/2 Vs
Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V
The difference in potential is
V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V
B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
C) The initial momentum is 12 kg*m/s, and the final momentum is 3 kg*m/s
D) The inital momentum is 6 kg*m/s, and the final momentum is 12 kg*m/s
Answer:
B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
Explanation:
The momentum of an object is given by the product between its mass (m) and its velocity (v):
Let's apply this formula to calculate the initial momentum and final momentum of the ball:
- initial momentum:
- Final momentum:
So, the correct answer is
B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
Answer:
No, the apple will reach 4.20041 m below the tree house.
Explanation:
t = Time taken
u = Initial velocity = 2.8 m/s
v = Final velocity = 0
s = Displacement
g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)
Equation of motion
The height to which the apple above the point of release will reach is 0.39959 m
From the ground the distance will be 1.3+0.39959 = 1.69959 m
Distance from the tree house = 5.9-1.69959 = 4.20041 m
No, the apple will reach 4.20041 m below the tree house.
The values in the option do not reflect the answer.
The apple will not reach the friend in the tree house as it will only reach a height of approximately 1.527 m.
To determine whether the apple will reach a friend in a tree house 5.9 m above the ground, we can use the equations of motion. Since the apple is thrown vertically upward, it will experience a negative acceleration due to gravity. Using the equation h = vo*t + (1/2)*a*t^2, where h is the final height, vo is the initial velocity, a is the acceleration, and t is the time, we can calculate the time it takes for the apple to reach a height of 5.9 m. Plugging in the values, we get:
5.9 = 2.8*t + (1/2)*(-9.81)*t^2
Simplifying the equation, we have:
-4.905*t^2 + 2.8*t - 5.9 = 0
Using the quadratic formula, we can solve for t. The quadratic formula is t = (-b ± sqrt(b^2 - 4ac)) / (2a), where a = -4.905, b = 2.8, and c = -5.9.
Plugging in the values, we get:
t = (-2.8 ± sqrt(2.8^2 - 4*(-4.905)*(-5.9))) / (2*(-4.905))
After evaluating the formula, we find that the apple will take approximately 1.527 seconds to reach a height of 5.9 m. Since the apple continues to rise after reaching this height, it will not reach the friend in the tree house.
Calculate the resultant force acting on the water skier while accelerating.