The volume of a sample of copper of 98.2 g would be 10.95 ml if the density of copper is 8.96 g/mL.
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
Due to their superior electrical and thermal conductivities, remarkable resistance to corrosion, and simplicity of production, copper alloys are frequently employed. In general, copper alloys are not magnetic. Electrical wire, cable, contacts, and other components.
As given in the problem the density of copper is 8.96 g/mL, and we have to find the volume occupied by the sample of copper.
mass = density×volume
98.2 g = 8.96 g/mL×volume
volume =98.2/8.96
=10.95 ml
Thus, the volume of a 98.2 g sample of copper would be 10.95 ml.
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Answer:
Density=mass/volume.
8.96=98.2/volume.
volume=98.2/8.96=10.95982143 ~ 11cm^3.
The correct answer to the question is : Mechanical energy.
EXPLANATION:
Let us consider a pendulum which is raised to certain height. The energy possessed by the pendulum at this height is gravitational potential energy.
Let the pendulum is released. Now the potential energy of the pendulum is converted into kinetic energy. At the mean point, whole of its potential energy is converted into kinetic energy.
Due to inertia, the pendulum will overshoot its mean position and will move towards its extreme position. During its movement from mean point to extreme point, the kinetic energy is converted into potential energy. At extreme point, whole of its kinetic energy is converted into potential energy.
Hence, there is only energy conversion between kinetic energy and potential.
We know that sum total of kinetic energy and potential energy is called mechanical energy.
Hence, the correct answer is mechanical energy.
a. True
b. False
Answer:
More powerful
Explanation:
I answered it and got it right.
Given:
V1 = 4m3
T1 = 290k
P1 = 475 kpa = 475000 Pa
V2 = 6.5m3
T2 = 277K
Required:
P
Solution:
n = PV/RT
n = (475000 Pa)(4m3) / (8.314 Pa-m3/mol-K)(290k)
n = 788 moles
P = nRT/V
P = (788 moles)(8.314 Pa-m3/mol-K)(277K)/(6.5m3)
P = 279,204 Pa or 279 kPa