A) 1 m/s
B) 2 m/s
C) 3 m/s
D) 6 m/s
Graph Attached*
Answer:
Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 2020 whhdbd dhd dvd s bs sbs shs shs sh s
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Answer:
294 J
Explanation:
To find the kinetic energy (KE) of a 3.00 kg toy falling from a height of 10.0 m, we'll use the kinetic energy formula: KE = 0.5 * m * v^2, where 'm' is the mass of the toy, and 'v' is its velocity.
We'll also apply the conservation of energy principle, which states that the total energy of an isolated system remains constant. This means that the gravitational potential energy (PE) of the toy at the initial height is equal to its kinetic energy just before hitting the ground.
The formula for gravitational potential energy is PE = m * g * h, where 'm' is the mass of the object, 'g' is the acceleration due to gravity, and 'h' is the height of the object.
So, we can equate these two expressions and solve for 'v':
0.5 * m * v^2 = m * g * h
v^2 = 2 * g * h
v = √(2 * g * h)
Plugging in the given values:
v = √(2 * 9.8 m/s² * 10.0 m)
v ≈ 14.0 m/s
Now that we have the velocity of the toy, we can calculate its kinetic energy using the KE formula:
KE = 0.5 * m * v^2
KE = 0.5 * 3.00 kg * (14.0 m/s)^2
KE ≈ 294 J
So, just before hitting the ground, the kinetic energy of the toy is approximately 294 joules.
Answer:
Force applied by bull dozer is 3333.33 joules.
Explanation:
Answer: A digatil is newer better
Explanation:
The moment of the couple formed by the two forces applied to the corners b and d of a rectangular plate, given that p = 88-n, is 7.33 N * m.
To resolve each force into horizontal and vertical components, we can use the following equations:
Horizontal component = P * cos(theta)
Vertical component = P * sin(theta)
where P is the magnitude of the force and theta is the angle between the force and the horizontal.
In this case, both forces are applied at a 50-degree angle to the horizontal. Therefore, the horizontal and vertical components of each force are:
Horizontal component = 88 N * cos(50 degrees) = 51.42 N
Vertical component = 88 N * sin(50 degrees) = 61.28 N
To calculate the moment of the couple, we need to multiply the force by the perpendicular distance between the line of action of the force and the origin of the moment. In this case, the perpendicular distance is the length of the plate.
The moment of the couple formed by the two forces is:
Moment = (51.42 N * 0.5 m) + (61.28 N * 0.3 m) = 7.33 N * m
Therefore, the moment of the couple formed by the two forces applied to the corners b and d of a rectangular plate, given that p = 88-n, is 7.33 N * m.
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