Match the following carbohydrate molecules with the class of molecule that they belong to:Molecules: (I) Glucose; (II) Starch; (III) Sucrose


Classes:

A) Polysaccharides
B) Disaccharides
C) Monosaccharides

Answers

Answer 1
Answer:
(I) Glucose; is C
(II) Starch; A
(III) Sucrose
B

A) Polysaccharides
B) Disaccharides
C) Monosaccharides

Monosaccharide, disaccharides, and polysaccharides are the three major categories of molecules in Carbohydrates. 

Monosaccharides, known as simple sugar, is the simplest form of carbohydrates. Its basic molecular formula is CH2O. Monosaccharides are glucose, fructose, and galactose. Its primary function is to be the source of energy of living organisms. It is also the primary requirement for the formation of disaccharides and polysaccharides.

Disaccharides are formed when two monosaccharides are bonded together through a covalent bond. Common Dissaccharides are sucrose  (glucose+fructose) or table sugar, maltose (glucose+glucose), and lactose (glucose+galactose). Its primary function is to provide nutrition for monosaccharides. Sugar in food is mostly dissaccharides.

Polysaccharides are formed when another monosaccharides is bonded to the disaccharides. This bond is called glycosidic bond. Two major polysaccharides are starch and glycogen. Starch is made by plants while glycogen is made by animals. Polysaccharides' major function is to immediately release energy from its storage. When glucose is consumed, some of them are stored and will only be released when the body needs it to satisfy the body's immediate need of energy.



Answer 2
Answer:

Final answer:

Glucose is a Monosaccharide, Starch is a Polysaccharide, and Sucrose is a Disaccharide. Monosaccharides are simple sugars, Disaccharides are two sugar molecules, and Polysaccharides are complex carbohydrates.

Explanation:

The carbohydrate molecules belong to the following classes:

  • (I) Glucose belongs to the class of Monosaccharides.
  • (II) Starch belongs to the class of Polysaccharides.
  • (III) Sucrose belongs to the class of Disaccharides.

To explain, Monosaccharides are the simplest form of carbohydrates, such as glucose. Disaccharides are two monosaccharide molecules linked together, in this case, sucrose is composed of glucose and fructose. Polysaccharides are complex carbohydrates, made of many sugar units - starch is one such example.

Learn more about Carbohydrate Classification here:

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classify each phrase as applying to the lytic cycle, the lysogenic cycle, or both types of reproductive cycles of phages.

Answers

In the lytic  cycle, a virus that has invaded and  entered a  cell takes over the cell's replication mechanism. The virus makes viral DNA and viral proteins.

The virus then lyses (breaks open) the cell membrane, allowing the newly  produced viruses to leave the now disintergrated host cell to infect  other new cells.


In a lysogenic cycle, the viral DNA or RNA enters the cell and integrates  into the host DNA as a new set of genes called prophage. The prophage is passive and non virulent and does not destroy the cell. However if the prophage undergoes any stress or mutation or is exposed to UV radiation, it may adopt the lytic cycle and become infective.

Describe what will happen to the water and 
sugar molecules when a cell is in an environment with a higher concentration of 
water and lower concentration of solute (sugar). Refer to the picture below in your answer.

Answers

Answer:

If the number of solute (sugar)  in the environment is less compared to the solute particles present in the inside such condition is called as hypo-tonic conditions.

Explanation:

Then water will move outside the cell.As the solution in which the cell is placed also has a higher concentration of water than the cell does, which makes Osmosis to draw water out of the solution and into the cells. As a result, plant and animal cells both appear more plump when placed in a hypo-tonic solution.

What are the stages of Meiosis I and Meiosis II in order as the happen.

Answers

Prophase I 

DNA replication precedes the start of meiosis I. During prophase I, homologous chromosomes pair and form synapses, a step unique to meiosis. The paired chromosomes are called bivalents, and the formation of chiasmata caused by genetic recombination becomes apparent. Chromosomal condensation allows these to be viewed in the microscope. Note that the bivalent has two chromosomes and four chromatids, with one chromosome coming from each parent.
Prometaphase I 

The nuclear membrane disappears. One kinetochore forms per chromosome rather than one per chromatid, and the chromosomes attached to spindle fibers begin to move.
Metaphase I 

Bivalents, each composed of two chromosomes (four chromatids) align at the metaphase plate. The orientation is random, with either parental homologue on a side. This means that there is a 50-50 chance for the daughter cells to get either the mother's or father's homologue for each chromosome.
Anaphase I 

Chiasmata separate. Chromosomes, each with two chromatids, move to separate poles. Each of the daughter cells is now haploid (23 chromosomes), but each chromosome has two chromatids.
Telophase I 

Nuclear envelopes may reform, or the cell may quickly start meiosis II.
Cytokinesis 

Analogous to mitosis where two complete daughter cells form.
Meiosis I: 

Prophase I - Homologus chromosomes pair up (synapsis) and form a tetrad. Sometimes non-sister chromatids exchange genetic information during the process of crossing over. 

Metaphase I- Tetrads line up at the center of the cell. 

Anaphase I - Homologous pairs are split up. 

Telophase I/Cytokinesis - Two daugher cells form that have half the chromosome number of the parent cell but each chromosome consists of a pair of sister chromatids. 

Interkinesis - break period 

Meiosis II: 

Prophase II - A new spindle forms 

Metaphase II- Each chromosome lines up at the middle of the cell. 

Anaphase II - The sister chromatids are separated and move to opposite ends of the cell. 

Telophase II - Two new nuclei are formed in each cell. Each nucleus contains a haplod (n) number of chromosomes. 

Cytokinesis- End result of meiosis is 4 haploid daughter cells

An animal is a vertebrate. It is warm-blooded and has feathers on its body. Which class does it belong to? Reptilia Aves Mammalia

Answers

Answer: Aves


Birds are warm blooded and have feathers

_________________________________________


Mammalia's are warm blooded but have hair that cover the body


Reptilia's are cold blooded and their bodies are usually covered in scales.  


Hopefully this helped and good luck!!!!


Answer:

The answer is Aves.

Explanation:

Hope this helped ya.

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Pancreatic cells, which secrete a large amount of digestive enzymes, are labeled with radioactive leucine and then chased for several hours withnonradioactive leucine. Photographic emulsions are prepared at different times during the chase. Where would the black spots appear on an emulsionprepared 3 hours after the pulse?- Rough ER
- Secretory vesicles
- Golgi apparatus
- Exterior of the cell

Answers

Answer:

The answer is:  Exterior of the cell.

Explanation:

Black spots would appear on the exterior of the cell after 3 hours, indicating that the proteins had been secreted from the cell.

This due to:

Exocytosis_ is the process of moving materials from within a cell to the exterior of the cell. This process requires energy and is therefore a type of active transport.

When a rock falls from outer space all the way to the ground, it is called a ______.

Answers

Answer:Meteoriet

Explanation:When its in space it is called a meteor but when it enters out atmosphere and hits the ground it turns into a meteorite