What is the answer for. What is hg = 45g

Answers

Answer 1

Answer: To solve hg = 45g

Apply Multiplication Property of Equality which is to multiply both sides of the equation with 1/g.

hg (1/g) = 45g (1/g)
   h = 45

Or you can divide both sides with the equation with g.

   hg / g = 45g / g

You can cancel g to both sides.
Then,
   h = 45

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The base b is not known 60 is 40% of what?

Answers

60 is 40% of 150

Change the percentage (40%) into a decimal by dividing over 100:

40/100 = 0.4

Divide 60 by the decimal (0.4):

60/0.4 = 150

Which of the following expressions is not equivalent to:4(3x2 + 6x)

A. 12x2 + 24x B. 2x(6x + 12) C. 6x(2x2 + 4x)

Answers

Answer=C

4(3x^2+6x)
can be simplified to...
12x^2+24x

To find out which expression isn't equivalent, you have to simplify them...

a=12x^x+24x

b=2x(6x+12)
b=12x^2+24x

c=6x(2x^2+4x)
c=12x^3+24x

-2 (x+11)= -2x-22 name the property of real number illustrated by the equation

Answers

Final answer:

The property of real numbers represented by the equation -2(x+11) = -2x-22 is the Distributive Property, which defines that a(b + c) = ab + ac handling multiplication and addition/subtraction.

Explanation:

The property of real numbers illustrated by this given equation -2(x+11)=-2x-22 is known as the Distributive Property. The Distributive Property can be defined as a(b + c) = ab + ac.

Applying this property to the equation, -2 is multiplied by each term inside the parentheses (x and 11), resulting in -2x-22, which matches the right side of the original equation.

Learn more about Distributive Property here:

brainly.com/question/6276874

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Distributive property
-2(x+11)=-2x-22
-2 times X
-2 times 11

given that the length of the class is 20m, breadth 10m, Door with the length 8m and breadth of 4m and windows with the length of 5m and breadth of 3m. Use scale of 5m;4cm to draw the plan of the class foundation plan

Answers

Answer:

Step-by-step explanation:

To draw the plan of the class foundation using a scale of 5m to 4cm, you'll need to create a scaled-down representation of the room, including the door and windows. Here are the steps to draw the plan:

1. Determine the size of your drawing area. Since the scale is 5m to 4cm, you need to calculate the dimensions of your drawing area.

Length of the class: 20m

Breadth of the class: 10m

Using the scale, for every 5 meters in reality, you will represent it as 4 centimeters in your drawing. So, you'll need a drawing area that can accommodate these dimensions, and the scale conversion.

Length of drawing area = (20m / 5m) * 4cm = 16cm

Breadth of drawing area = (10m / 5m) * 4cm = 8cm

Therefore, your drawing area should be approximately 16cm by 8cm.

2. Draw the outline of the class: Using a ruler and a pencil, draw a rectangle with dimensions 16cm by 8cm to represent the classroom. This rectangle represents the foundation of the class.

3. Draw the door: The door is 8 meters long and 4 meters wide. Using your scale, you'll represent it as 4cm by 2cm in your drawing. Draw a rectangle within the classroom rectangle to represent the door. The top edge of the door should align with one of the longer sides of the classroom.

4. Draw the windows: The windows are 5 meters long and 3 meters wide. Using your scale, you'll represent each window as 4cm by 2.4cm in your drawing. Place the windows where they would be on the classroom walls, leaving space between them and the door.

5. Label the drawing: You can label the door and windows to indicate their dimensions if needed.

What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?(A. y+2 = -2(x+5); B. y-2 = 2(x-3); C. y-3 = 2(x-2); D. y+3 = -2(x+2))

Answers

Hi,

m = (y-y₀)/(x-x₀)
m = (-5-3)/(-2-2)
m = -8/-4
m = 2

For point (2,3) ⇒ x₀ = 2 and y₀ = 3

y-y₀ = m(x-x₀)
y-3 = 2(x-2)

For point (-2,-5) ⇒ x = -2 and y = -5

-5-3 = 2(-2-2)
-8 = 2(-4)
-8 = -8 ⇒ True

Answer:

C. The equation is y-3 = 2(x-2)

To solve the equation below by completing the square what is the first step? 4x^2+16x=20

A. add 8 to each side of the equation.
B. add 64 to each side of the equation.
C. multiply both sides of the equation by 1/4.
D. multiply both sides of the equation by 1/8.

Answers

C multiply both sides of the eaqaution by 1/4

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