The sides of a triangle are in the ratio of 6:8:10 and its perimeter is 720 cm. Find its area.

Answers

Answer 1

Answer:

216m²

Given that the sides of a triangle are in the ratio of 6:8:10 and their perimeter is equal to 720cm.

To find the area, we would use heron's formula which says area = √[s(s-a)(s-b)(s-c)] ,where a,b,c are the respective sides of the triangle and s = perimeter/2 but before that,we would need to find out the sides , for that , let's say the sides are equal to 6x ,8x & 10 x.

Then,

ATQ,

6x + 8x +10x = 720cm

24x = 720cm

x = 720cm/24

x = 30cm

therefore,

6x = 6*30cm = 180cm

8x = 8*30cm = 240cm

10x = 10*30cm = 300cm

and

s = 720cm/2 = 360cm

Now,

using heron's formula,

area = √[s(s-a)(s-b)(s-c)]

area = √[360cm(360cm-180cm)(360cm-240cm)(360cm-300cm)

area = √[360cm*180cm*120cm*60cm]

area = √(466,560,000cm⁴)

area = 21,600cm² or 216m²

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A rectangular prism with a length of 22 meters a width of 18 meters and a height of 10 meters A) 3247 sq.m
B) 2563 sq.m
C)1592 sq.m
D) 1789 sq.m

Answers

Answer:

the answer is 1240

Step-by-step explanation:

1st you have to find the area of each surface and then add all the numbers together

(22x10)+(22x10)+(22x10)+(22x10)+(18x10)+(18x10)

then solve

220+220+220+220+180+180

1240

Find the least common multiple of 7 3 2

Answers

The answer should be 42

What is the common difference between successive terms in the sequence?0.36, 0.26, 0.16, 0.06, –0.04, –0.14,

Answers

the common difference between successive terms

To find the common difference we subtract the first term from second term

0.36, 0.26, 0.16, 0.06, –0.04, –0.14,

0.26 - 0.36 = -0.10

0.16 - 0.26 = -0.10

0.06 - 0.16 = -0.10

-0.04 - 0.06 = -0.10

-0.14 - (-0.04) = -0.10

We can see that the common difference is =0.10

the common difference between successive terms = -0.10

The correct answer is:

-0.10.

Explanation:

The common difference between successive terms in a sequence is the number you add to each term to find the next one.

To find this number, you can subtract the first term from the second, the second from the third, and so on:

0.26-0.36 = -0.10

0.16-0.26 = -0.10

0.06-0.16 = -0.10

-0.04-0.06 = -0.10

-0.14--0.04 = -0.10

The common difference is -0.10.

Use an inequality symbol (<, >, =, ≤) to compare −3 + 7 _____ −10 − 2 A. > B. < C. = D. ≤

Answers

By using the concept of inequality, the solution for the correct inequality used between the given numbers is,

$(- 3 + 7 ) > (- 10 - 2)$

Used the concept of inequality, which states that,

A relation by which we can compare two or more mathematical expressions is called an inequality.

Given that,

Compare the numbers (- 3 + 7) and ( - 10 - 2).

Now, to compare the numbers we can solve each side,

(- 3 + 7) = - 3 + 7

= 7 - 3

= 4

(- 10 - 2) = - 10 - 2

= - 12

So, by the definition of positive and negative numbers, we get,

4 > - 12

As positive numbers are always greater than negative numbers.

To learn more about inequality visit:

brainly.com/question/25944814

#SPJ4

A would be the best choice because -3 + 7 is 4 and -10 - 2 is -12.

The width of a rectangle is 12 cm less than the length. The perimeter is 156 cm. Find the width and length.

Answers

$w-the\ width\nl-the\ length\n\nw=l-12\n\nthe\ perimeter\ of\ rectangle:P=2(w+l)\ and\ P=156cm\n\n2(w+l)=156\to\ put\ w=l-12\ to\ equation:\n\n2(l-12+l)=156\n2(2l-12)=156\ \ \ \ |divide\ both\ sides\ by\ 2\n2l-12=78\ \ \ \ \ |add\ 12\ to\ both\ sides\n2l=90\ \ \ \ \ |divide\ both\ sides\ by\ 2\nl=45\n\nw=45-12=33\n\nSolution:the\ width\ equal\ 33cm\ and\ the\ length\ equal\ 45cm.$

there are 94 suitcases in number one cargo bin. there are two cargo bins to be loaded on the airplane. the second bin contains 214 suitcases and the third 103 suitcases. if all three of these cargo bins are loaded onto the 747 airplane,how many total suitcases will be in the cargo area?

Answers

isnt it simple addition? i'm aint sure because i'm french but if i understand well, it suppose to be 411

Final answer:

The total suitcases in all three cargo bins, when added up (94 + 214 + 103), equals 411. Consequently, there will be 411 suitcases in the cargo area of the 747 airplane.

Explanation:

Total suitcase calculation involves simply adding up the numbers from all three cargo bins. The first bin contains

94 suitcases, the second bin 214 suitcases, and the third contains 103 suitcases. Adding all these up gives a total suitcase number as follows: 94 + 214 + 103 = 411. Therefore, if all these cargo bins are loaded onto the 747 airplane, here will be 411 suitcases in the cargo area.