Joe walked a distance of 1.5 miles across the park to get to school.
And the difference in their 2 round trips is 1.2 miles.
Pythagoras' Theorem states that the square of the hypotenuse side of a right-angled triangle is equal to the sum of the squares of the other two sides.
We can use the Pythagorean theorem to find the distance that Joe walked today.
Let's call this distance d.
Since Joe walked a straight path across the park, the distance he covered can be represented by the hypotenuse of a right triangle, with Main Street and Washington Avenue as the legs.
Now,
d² = 1.2² + 0.9²
d² = 1.44 + 0.81
d² = 2.25
d = 1.5
Therefore, Joe walked a distance of 1.5 miles across the park to get to school.
To find the difference in distance between the two round trips, we can subtract the distance that Joe usually walks from the distance he walked today, and double the result, since he has to walk back home.
Hence,
2 × (-1.5 + 1.2 + 0.9) = 1.2 miles
Therefore, the required distance is 1.2 miles.
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Answer:
x=1.5
Step-by-step explanation:
you divide 9 by 6 to get x
9÷6=1.5