b. the distance a spring stretches has nothing to do with how much force is applied to it.
c. as the force on a spring increases, the distance it stretches increases.
d. as the force on a spring increases, the distance it stretches decreases.
Answer: option c. as the force on a spring increases, the distance it stretches increases.
Explanation:
Hooke's Law relates the force (F) applied on the spring and extension (x) of the spring:
F = - k x
Where, k is the spring constant.
as the force on a spring increases, the distance it stretches increases but it is limited by its elastic limit. The negative sign means that spring force is a restoring force which means that the stretch of the spring is in opposite direction to force.
330 m
990 m
0.5 m
Answer:
The wavelength of the sound wave traveling at 330 m/s is 0.5 m.
Explanation:
Given:
Speed of sound wave is,
Frequency of the sound wave is,
Speed of a sound wave is related to its frequency and wavelength as:
, where, is the wavelength.
Now, plug in 330 for , 660 for and solve for . This gives,
Therefore, the wavelength of the sound wave traveling at 330 m/s is 0.5 m.
Calculate the current in the 200.-ohm resistor.
Answer:
current in 200ohm resistor = 0.05A
Explanation:
for current in 200 ohm resistor,
let 'I2' and 'R2' be current and resistance in 200 ohm resistor,
potential difference remains same thorughout the circuit because they are connected in parallel,
we have,
V=10V
R2=200 ohm
I2=?
then by ohm's law,
V=I2*R2
10=I2*200
I2=0.05A
The power dissipated by the 100-ohm resistor is 400 watts. The current in the 200-ohm resistor is 0.05 Amps.
To determine the power dissipated by the 100-ohm resistor, we can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance. Since the current is the same throughout a parallel circuit, the current flowing through the 100-ohm resistor is the same as the total current in the circuit. Using the formula P = I^2 * R, we can calculate the power dissipated by the 100-ohm resistor as P = (2.00 A)^2 * 100 ohms = 400 watts.
To calculate the current in the 200-ohm resistor, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the voltage supplied by the battery is 10.0 volts. Using Ohm's Law, we can calculate the current in the 200-ohm resistor as I = V / R = 10.0 V / 200 ohms = 0.05 Amps.
#SPJ2
B) Image B
C) Image C
D) Image D
Answer:
Image B represents the force on a positively charged particle caused by an approaching magnet.
Explanation:
The most fundamental law of magnetism is that like shafts repulse each other and dissimilar to posts pull in one another; this can without much of a stretch be seen by endeavoring to put like posts of two magnets together. Further attractive impacts additionally exist. On the off chance that a bar magnet is cut into two pieces, the pieces become singular magnets with inverse shafts. Also, pounding, warming or winding of the magnets can demagnetize them, on the grounds that such dealing with separates the direct game plan of the particles. A last law of magnetism alludes to maintenance; a long bar magnet will hold its magnetism longer than a short bar magnet. The domain theory of magnetism expresses that every single enormous magnet involve littler attractive districts, or domains. The attractive character of domains originates from the nearness of significantly littler units, called dipoles. Iotas are masterminded in such a manner in many materials that the attractive direction of one electron counteracts the direction of another; in any case, ferromagnetic substances, for example, iron are unique. The nuclear cosmetics of these substances is with the end goal that littler gatherings of particles unite as one into zones called domains; in these, all the electrons have the equivalent attractive direction.
A positively charged particle will be deflected by the magnetic force when it approaches a magnet. Look for an image in which the particle's path deviates away from the magnet. Without the images, a specific selection cannot be made.
The question relates to the force exerted by a magnet on a positively charged particle. A magnet has two poles, North and South. A positively charged particle moving towards a magnet will be deflected by the field, with the direction of deflection dependent on the specific pole it is approaching. Without the images being provided, it's hard to give a definite answer. However, you should look for an image where the particle's path deviates away from the magnet, as this represents the magnetic force applied to it.
Learn more about Magnetic Force here:
#SPJ3