Answer:
Explanation:
because it wouldnt connect
The speed of the car is 75 km/h
These are the formulas that we have to remember before solving the problem.
Speed is the rate of change of distance.
v = speed ( m/s )
d = distance ( m )
t = time ( s )
Acceleration is the rate of change of velocity.
a = acceleration ( m/s² )
Δv = change in speed ( m/s )
t = time ( s )
Let us now tackle the problem!
Given:
distance = d = 150 km
time taken = t = 7200 s = 2 hours
Unknown:
velocity = v = ?
Solution:
The acceleration of the car is 0 m/s² because it travels with constant speed.
We could also plot the distance vs time graph as shown in the attachment.
Grade: Middle School
Subject: Physics
Chapter: Kinematics
Keywords: indycar top speed of a fastest police car has ever gone
The car's speed is 75 km/hour, as determined by dividing the total distance travelled (150 km) by the total time taken (2 hours).
To answer this question, we use the
formula for speed
, which is distance traveled divided by the time taken. Here, the distance travelled by the car is 150 km and the time taken is 7200 s (which is equal to 2 hours). Therefore, the speed will be 150 km divided by 2 hours, resulting in a speed of
75 km/hour
, stated to the correct number of significant figures.
#SPJ6
A) equal
B) half as much
C) twice as much
D) four times as much
Answer: C
Explanation:
Calculate EkA -kinetic energy of car A
m=1000kg
Va=16.66 m/s
EkA=m*Va²/2
Eka=(1000kg*277.556m²/s²)/2
Eka=138 777.8 J
Calculate kinetic energy of CarB:
m=2000 kg
Vb=8.33 m/s
Ekb=(m*Vb²)/2
Ekb=(2000kg*69.39m²/s²)/2
Ekb=69 388.9 J
compare Eka with EkB
Eka/Ekb=138 777.8 J/69 388.9
Eka/Ekb=2
The kinetic energy of car A is twice as much as that of car B. This is calculated using the formula for kinetic energy, which is 1/2 * mass * (velocity)^2.
To compare the kinetic energy of car A with that of car B, we first need to understand the mathematical formula for kinetic energy, which is 1/2 * mass * (velocity)^2.
Let's calculate for each car:
Therefore, car A has twice as much kinetic energy as car B.
#SPJ3
in cgs system, plank's constant= h=6.626 x10⁻²⁶ erg s
Value of Plank's constant in SI system= 6.626 x10⁻³⁴ Js
now 1 Joule= 10⁷ ergs
so h= 6.626 x10⁻³⁴ Js (10⁷ ergs/1J)
h=6.626 x10⁻²⁷ erg s