Advance tickets for a school play went on sale. The price of each student ticket was $4 and everyone else paid $5. On the first day, no more than $80 in tickets were sold. Describe and explain the possible values of s, the number of student tickets sold, and e, the number of tickets sold to nonstudents.

Answers

Answer 1

Answer:

The no. of possible solutions is 4 they are (s, e) ⇒ (1, 4), (2, 2), and (4, 1).

What is a linear equation?

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Given, Advance tickets for a school play went on sale.

The price of each student ticket was $4 and everyoneelse paid $5.

's' is the number of student tickets sold, and 'e', is the number of tickets sold to nonstudents and

No more than $80 in tickets were sold.

∴ 4s + 5e ≤ 80.

So, the possible solution are the sum of the multiples of 4 and 5 which results in 80.(only integer values)

4s + 5e ≤ 80.

4s ≤ 80/5e.

Now, when e = 1 , s = 4,

when e = 2 , s = 2,

when e = 4, s = 1.

So, the possible solutions are (1, 4), (2, 2), and (4, 1).

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Answer 2

Answer:

Answer:

Partial and negative tickets cannot be sold, so the minimum number values of e and s are 0. If s = 0, then e = 16, and if e = 0, then s = 20. Therefore, the values of s are whole numbers from 0 to 20 and the values of e are whole numbers between 0 and 16. The greatest number of student tickets sold was 20 and the greatest number of nonstudent tickets sold was 16.

Step-by-step explanation:

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