MATHEMATICS HIGH SCHOOL

The school is 3.2 blocks from Hector's house.How many blocks does Hector walk to go to and from school

Answers

Answer 1

Answer:

The number of blocks Hector walk to go to and from school is:

6.4 blocks.

Step-by-step explanation:

It is given that:

The school is 3.2 blocks from Hector's house.

We are asked to find:

How many blocks does Hector walk to go to and from school.

This means that we have to find the number of blocks he covers in both ways of his journey.

The number of blocks he goes from House to school are same for his return journey.

Hence, the total number of blocks he cover while going and returning to his house is:

3.2+3.2=6.4 blocks.

Answer 2

Answer: 3.2 + 3.2= 6.4
Why did I do this?
Because it says how many blocks does he walk to school and back.

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What is the distance between points A and B? please help!! WILL MARK BRAINLIEST!!!!

A. 29
B. 2 V 29
C. 3 V 14
D. V58

Answers

Answer:

The answer should be 7.615773...

or $\sqrt58$

Step-by-step explanation:

$\sqrt(x^(2) -x^(1) )^(2) +(y^(2) -y^(1) )^(2) \n\n\n\sqrt(11^(2) -4^(1) )^(2) + (7^(2) - 4^(1) )^(2)\n\n \n\sqrt58 = 7.61577310586...\n$

I hope this helps.

PLEASE HELP. A playground is shaped like a rectangle with a width 5 times its length (l). What is a simplified expression for the distance between opposite corners of the playground?

Answers

Look at the picture.

Use the Pythagorean Teorem:
$l^2+(5l)^2=d^2\nl^2+5^2l^2=d^2\nd^2=l^2+25l^2\nd^2=26l^2\nd=√(26)^2\nd=√(26)\cdot√(l^2)\n\boxed{d=l√(26)}$

Julia is saving money for the down payment on a car. She plans to save for one year. Her parents have offered to contribute $50 a month to her savings. How much does Julia need to save each month in addition to her parents' contribution if she wants to have a $2700 down payment on a car at the end of the year? Define a variable and write an equation to represent this situation.

Answers

Answer:

$12x+600=2700$

$175

Step-by-step explanation:

Let x represent money saved by her in one month.

So money saved by her in one year (12 months) would be $12x$ .

We can represent our given information as:

$12x+600=2700\n12x=2700-600\n12x=2100\nx=(2100)/(12)\nx=175$

Therefore, she needs to save $175 per month.

Describe this pattern. Then see if you can think of another Pythagorean triple that doesn't follow the pattern you just described and that can't be generated using the identity (x2 − 1)2 + (2x)2 = (x2 + 1)2. Explain your findings. x-value Pythagorean Triple 7 (14,48,50) 8 (16,63,65) 9 (18,80,82) 10 (20,99,101)

Answers

Answer:

See explanation

Step-by-step explanation:

A Pythagorean triple is a set of 3 positive integer numbers, a, b, and c which satisfies the Pythagorean theorem: $c^2=a^2+b^2$

Given the identity: $(x^2 - 1)^2 + (2x)^2 = (x^2 + 1)^2.$

We verify that the numbers given table are Pythagorean triples.

$14^2+48^2=2500=50^2\n16^2+63^2=4225=65^2\n18^2+80^2=6724=82^2\n20^2+99^2=10201=101^2$

Next, we examine the pattern:

$\left|\begin{array}{c|c|c|c|c}x-value&x^2-1&2x&x^2 + 1&$Triple\n--&--&--&--&----\n7&48&14&50&(14,48,50)\n8&63&16&65&(16,63,65)\n9&80&18&82&(18,80,82)\n10&99&20&101&(20,99,101)\end{array}\right|$

From the pattern, our first number is 2x, the second number is x² - 1, and the third number(hypotenuse) is x² + 1

Next, we show that (x² - 1)² + (2x)² = (x² + 1)² is an identity

$LHS: (x^2 - 1)^2 + (2x)^2 \n= (x^2-1)(x^2-1)+2x^2\n=x^4-2x^2+1+4x^2\n=x^4+2x^2+1$

$RHS: (x^2+1)^2\n= (x^2+1) (x^2+1)\n=x^4+2x^2+1$

Since Left Hand Side=Right hand Side. For all x, the equation is always true.

Therefore, the pattern is true for any Pythagorean triple.

How many solutions does this system have?Y=x+5
Y=-5x-1

One
None
Infinite
Two

Answers

Infinite
Put both in on Desmos calculator and all the point its give you is about 5+ different ones

Which statement can be used to prove that a given parallelogram is a rectangle?The diagonals of the parallelogram are congruent.

The opposite angles of the parallelogram are congruent.

The diagonals of the parallelogram bisect the angles.

The opposite sides of the parallelogram are congruent.

Answers

the answer for this is the very last one

The diagonals of the parallelogram are congruent.

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