What are the solutions to the quadratic equation 4x2 + 28x = 0?

Answers

Answer 1

Answer: see attached picture for answer

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How do you write 2.6 × 10 to the 3 power in standard form?
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Point A, located at (-2, 4), is translated down 6 units. What are the coordinates of A'?(-8, 4)
(-8, -2)
(-2, -2)
(-2, 4)

Answers

(-8, 4) hope that helps

Answer:

8,4

Step-by-step explanation:

Choose the symbol that will create a true sentence when m=20.100 - 2m___3m
a >
b =
c <
d ≤

Answers

100-2(20)=60
3(20)=60

B. =

   100 - 2m = 3m
100 - 2(20) = 3(20)
    100 - 40 = 60
   60 = 60
The answer is equal to B.

What is the coefficient of x in the division (18x^3+12x^2-3x)/6x^2?A.
3

B.
2

C.
-0.5

D.
-3

Answers

Answer:

Step-by-step explanation:

Given : $(18x^3+12x^2-3x)/(6x^2)$

To Find: What is the coefficient of x in the division

Solution:

$(18x^3+12x^2-3x)/(6x^2)$

On Dividing we

Quotient = 3x+2

Remainder = -3x

So, coefficient of x in quotient = 3

Thus the coefficient of x in the division $(18x^3+12x^2-3x)/(6x^2)$ is 3

Hence Option A is correct

That would be A.... when you divide the trinomial in bracket by the $6x^(2)$ you will realize that the coefficient of the x is 3. If you want me to send a picture of the division please indicate.

Use long division to find the quotient.

(x²+6x-27) ÷ (x-3)

Answers

$( x^2+6x-27 )/(x-3) = ( x^2+6x +3x-3x-27 )/(x-3) = ( x^2+9x-3x-27 )/(x-3) = \n \n =( x(x +9 )-3(x+9) )/(x-3) = ( (x +9 ) (x-3) )/(x-3) = x+9 \n \n \n x-3\neq 0 \nx\neq 3\nD=R\setminus \left \{ 3 \right \}$

The equation of a parabola is shown.x-7=3/4y^2
What are the coordinates of the focus?
A.) (71/3,0)
B.) (7,-1/3)
C.) 73/4,0)
D.) 7,-3/4)

Answers

The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)

Manipulating the given equation to the general form:
4(1/3)(x-7)^2 = (y - 0)^2

Therefore the coordinates of the focus is:
(7+(1/3),0)

The answer is A.) (71/3,0)

The measurement of a rectangular dam are:length =60-2x width=2x depth=x/2 determine the volume of the damin terms of x

Answers

Volume of this rectangular dam=lenght x width x depth
Data:
lenght=60-2x
width=2x
depth=x/2

V(x)=(60-2x)(2x)(x/2)
v(x)=(120x²-4x³)/2
v(x)=60x²-2x³

The volume of the rectangular dam is V(x)=60x²-2x³

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