77 ¹¹/₃₂ in²
The area that he can cover with these tiles is 77 ¹¹/₃₂ in²
Further explanation
To solve the above questions, we need to
recall some of the formulas as follows:
Area of Square = (Length of Side)²
Perimeter of Square = 4 × (Length of Side)
Area of Rectangle = Length × Width
Perimeter of Rectangle = 2 × ( Length + Width )
Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Rhombus = 4 × ( Length of Side )
Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )
Let us now tackle the problem !
Given:
Number of Tiles = N = 9 tiles
Length of Tiles = L = 3¹/₈ inches
WIdth of Tiles = W = 2³/₄ inches
Unknown:
Total Area = A = ?
Solution:
Area of One Tile.
Area of Rectangle=Length×WidthArea of Rectangle=Length×Width
Area of Rectangle=318×234Area of Rectangle=381×243
Area of Rectangle=81932 in2Area of Rectangle=83219 in2
Total Area.
Total Area=Number of Tiles×Area of One TileTotal Area=Number of Tiles×Area of One Tile
Total Area=9×81932Total Area=9×83219
Total Area=771132 in2Total Area=773211 in2
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h < 4a – 3 for values of a between 1 and 10
Which pair of values satisfy this inequality?
a. h = 2 and a = 1
b. h = 6 and a = 2
c. h = 10 and a = 3
d. h = 20 and a = 6
10.50*30 = 315
315*1000= 315,000
So 315,000 is the answer
A. Increase
B. Decrease
C. No effect
Answer:
Decrease I think.
Sorry if it is wrong.
Hope it helped :)
Plot your answer on the number line.
Answer:
Step-by-step explanation:
The absolute value of a number is its distance from zero on the number line, regardless of whether the number is positive or negative. To find the absolute value of a fraction like -3/4, you simply disregard the negative sign and take the positive value of the fraction:
Absolute value of -3/4 = 3/4
So, the absolute value of -3/4 is 3/4.
Answer:
total distance = 1 miles
Step-by-step explanation:
According to the information given below from the picture, the distance from the guy's house to the school is given as 5/10 miles.
5/10 miles can still be reduced to the lowest fraction as 1/2 miles.
Since he works to and fro from his house to school and school to house, The distance he covered will be the sum of the distance from house to school and school to house .
Distance from house to school = 1/2 miles
Distance from school to house = 1/2 miles
The total distance he covered = 1/2 miles + 1/2 miles
total distance = 1 miles