Answer:
Area of shaded region = 329.70 cm²
Step-by-step explanation:
Area of a circle = πr²
Area of bigger circle = 3.14 × 11²
= 3.14 × 11 × 11
= 379.94 cm²
Area of smaller circle = 3.14 * 4²
= 3.14 × 4 × 4
= 50.24 cm²
Area of shaded region
= Area of bigger circle - Area of smaller circle
= (379.94 - 50.24) cm²
= 329.70 cm²
Answer:
329.70 cm^2
Step-by-step explanation:
Hope this helps!
Answer: 250.5g of meat per guest
Step-by-step explanation:
Convert kg to gram to be in the same unit, 1kg = 1000g; therefore multiply 4.008kg by 1000= 4008g
With 4008g of meat available, Divide the available gram of meat by the number of guests
=4008g÷ 16
=250.5g is available per guest
I hope this helps.
Answer:
the cost of zero bags of candy
Step-by-step explanation:
What is P(A or B), the probability that the first die is six or the second die is four?
The formula for probability is given as:
Probability = Number of requiredevents / Totalnumber of outcomes.
P(A) = 6/36 = 1/6
P(B) = 6/36 = 1/6
P(A ∩ B) = 1/36
The probability that the firstdie is six or the seconddie is four.
= P(A U B)
= P(A) + P(B) - P(A ∩ B)
The probability that the firstdie is six or the seconddie is four is 11/36 .
It is the chance of an event to occur from a totalnumber of outcomes.
The formula for probability is given as:
Probability = Number of requiredevents / Totalnumber of outcomes.
We have,
The number of possibleoutcomes in the samplespace of rolling two dice.
n(S) = 6 x 6 = 36
A = event that the firstdie is a six.
A = { (6,1), (6,2), (6, 3), (6, 4), (6, 5), (6, 6) }
n(A) = 6
B = event that the seconddie is a four.
B = { (1, 4), (2, 4), (3, 4), (4, 4), (5, 4), (6, 4) }
n(B) = 6
Now,
P(A) = 6/36 = 1/6
P(B) = 6/36 = 1/6
P(A ∩ B) = 1/36
Now,
The probability that the firstdie is six or the seconddie is four.
= P(A U B)
= P(A) + P(B) - P(A ∩ B)
= 1/6 + 1/6 - 1/36
= 2/6 - 1/36
= (12 - 1)/36
= 11/36
Thus,
The probability that the firstdie is six or the seconddie is four is 11/36.
Learn more about probability here:
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Answer:
11/36
Step-by-step explanation:
First die 6: 6 possibilities
Second die 4: 6 possibilities
Intersection: 1 possibility (6,4)
P(A or B) = (6 + 6 - 1)/36
11/36