8% per annum and for the other 6% per annum. The total
interest paid for one year was Rs. 135. How much did he
borrow at each rate?
Solution:
A merchant borrowed Rs. 2000 from two money lenders
Let the sum at 8 % be x
Then, the sum at 6 % be 2000 - x
The total interest paid for one year was Rs. 135
8 % of x + 6 % of (2000 - x) = 135
Divide both sides by 0.02
x = 750
Then,
2000 - x = 1250
Thus, Rs 750 was borrowed at 8 % interest rate and Rs 1250 was borrowed at 6 % interest rate
Answer:
b
Step-by-step explanation:
hydrogen in moles per liter. If the pH of
Bill's swimming pool is 7.8 and the pH of
Maura's swimming pool is 7.2, whose
pool has a greater concentration of
hydrogen? How many times greater is it?
Answer:
Step-by-step explanation:
The logarithm function is monotonic with a positive slope everywhere. So, the logs of numbers are in the same order as the numbers themselves. pH is the negative of the logarithm, so the pH values are in the reverse order of the numbers themselves.
Maura's pool has a lower pH, so will have a higher concentration of hydrogen ions.
The log of a ratio is the difference of the logs. Here, the difference of the logs is 7.8 -7.2 = 0.6, so the ratio of H+ concentrations in the two pools is ...
10^0.6 ≈ 4.0
Maura's pool has 4× the H+ concentration of Bill's pool.
Answer:
your friends skateboard is higher
Step-by-step explanation:
If you do the problem, and need work, do this, convert 2 3/8 to a decimal as well as 2 2/5. Which ever one is bigger as a decimal is the higher one.