The fraction number 77/6 in the form of a mixed fraction number will be 12 ⁵/₆.
Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
The fraction number is given below.
⇒ 77 / 6
Convert the fraction number into a mixed fraction number. Then we have
⇒ 77 / 6
⇒ 12 + 5/ 6
⇒ 12 ⁵/₆
The fraction number 77/6 in the form of a mixed fraction number will be 12 ⁵/₆.
More about the Algebra link is given below.
#SPJ5
Answer:
12
Step-by-step explanation:
= 12 remainder 5
The remainder of 5 forms the numerator of the fractional part of the mixed number while the denominator remains as 6
= 12 ← mixed number
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
9. Think of another quadratic equation that has one (1) real number solution. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
10. Think of another quadratic equation that has no (0) real number solutions. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
explain your answer Please!
Answer:
Step-by-step explanation:
You just have to subtract 1/3x on both sides of the equation to cancel the 1/3x on the left.
I'd say there are two possibilities: the trivial choice of p=1 and starting number 4 (so you're summing one consecutive integer starting from 4), or you choose p = 8 and start from -3, so that all numbers from -3 to 3 simplify and you're left with 4 alone:
The problem does not provide enough information to find a unique value of 'p', the number of consecutive integers that sum up to 4. If we started the series at 1, for instance, 'p' would equal 4 (from 1+2+3+4=10), but if we were only considering positive integers and started the series at 2, 'p' would be 3, and so forth. Therefore, more information would be needed to solve this problem.
The subject of this question is in the domain of mathematics, specifically working with sums of consecutive integers. Based on the information given in the question, we are looking for the number of consecutive integers (or 'p') that add up to 4.
The formula used for the sum of consecutive integers is (n/2) (first number + last number), where n is the number of integers (in this case, 'p').
However, the question doesn't provide enough information to specify unique values for ‘p’. Any single set of consecutive integers that includes 4 (like 1,2,3,4 or -1,0,1,2,3,4,5,6,7,8,9) or the sum of 4 and 0 would satisfy the given condition, so 'p' could have multiple answers depending on the starting point of the series of integers.
#SPJ11
Answer:
Its the rate of the straight line on a graph