Is the gcf of a pair

Answers

Answer 1

Answer: A gcf is the Greastest comman factor like 4 and 8 there GCF is 4

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1 pair of opposite sides that are parallel
Can someone please help me with this? Thank you!
7w/4+3=9w/10+6I really need help on this
Sandy collects two shells at a time to Shawn collect for shells at a time and Sonya collect 10 shells at a time to have the same number of shells what is the least number of shells each friend must collect

What is - 6 (a+8) using the distributive property and simplify each expression

Answers

-6a - 48

hope this helps

-6(a+8)
-6x8=-48
a= -48

Write a number that has the zero in the tens place draw a quick picture for your number

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50. The tens place is just the second number. So 10, 20, 30, 40, 50, 60, 70, 80, 90. Every one of those can work.

17 points!!!
What is the missing exponent?

(2^-5) ????? = 2^-15

Answers

$(2^-^5) ^x = 2 ^ - ^1^5 \n \n ( (1)/(32) ) ^x = (1)/(32768) \n \n \hbox{Solve the exponent.} \n \n ( (1)/(32))^x = (1)/(32768) \n \n\hbox{Take log of both sides} \n \n \hbox{log}} ( (1)/(32)) ^ x = log ( (1)/(32768)) \n \n x * log ((1)/(32) ) = log ( (1)/(32768) ) \n \n \bold{ (log( (1)/(32768)))/(log (1)/(32) ) } \n \n x = 3$

Therefore the missing exponent is 3. Which makes the equation true.

${ \left( { 2 }^( -5 ) \right) }^( x )={ 2 }^( -15 )\n \n { 2 }^( -5x )={ 2 }^( -15 )\n \n \therefore \quad -5x=-15\n \n \therefore \quad x=3$

Remember that:

${ \left( { a }^( m ) \right) }^( n )={ a }^( m\cdot n )$

You are fencing in an area to make a garden. You only have 150 feet of fence. You want the length of the garden to be at least 40 feet. You want the width to be at least 5 feet. What is the graph showing the all of the possible dimensions your garden could have?

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Answer:

1200

Step-by-step explanation:

MULTIPLY AND DIVIDE

How do I solve this? Please show steps if you can

Answers

2r = 5s/2 - s/4
2r = 10s-s /4 [ took LCM of 4 & 2 ]
2r = 9s/4
9s = 2r*4
s = 8r/9

In short, your answer would be 8r/9

hope this helps!

the answer is r=9/8s

a kayaker travels x miles per hour downstream for 7 hours. on the 10-hour return trip, the kayaker travels 3 miles per hour slower. how far did the kayaker travel in total?

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im just here for the points

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