In the year 2002, the world population was estimated at 6 billion people. Based on research from the World Bank, about 20% lived on less than $1 per day. How many people lived on less than $1 per day?
Answers
6 billion = 6000000000
Now
Number of people earning less that $1 per day = (20/100) * 6000000000
= 6000000000/5
= 1200000000
So the number of people earning less than $1 per day is 1200000000
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Answer:
3.
Step-by-step explanation:
This is a geometric series so the sum is:
a1 * r^n - 1 / (r - 1)
= 1 * (2^101 -1) / (2-1)
= 2^101 - 1.
Find the remainder when 2^101 is divided by 7:
Note that 101 = 14*7 + 3 so
2^101 = 2^(7*14 + 3) = 2^3 * (2^14)^7 = 8 * (2^14)^7.
By Fermat's Little Theorem (2^14) ^ 7 = 2^14 mod 7 = 4^7 mod 7.
So 2^101 mod 7 = (8 * 4^7) mod 7
= (8 * 4) mod 7
= 32 mod 7
= 4 = the remainder when 2^101 is divided by 7.
So the remainder when 2^101- 1 is divided by 7 is 4 - 1 = 3..
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What number is 60% of 25?
60 ÷ 100 = 0.6
0.6 · 25 =15
Answer:- 15 is 60% of 25
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3, 3 ,3 ,7 ,8 ,8 ,11 ,11 ,13 ,14 ,15 ,17, 18, 19, 21, 23, 23 ,25,27, 28, and 29.
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= 4+ 0.15
= 4+ 15/100
= 4+ 3/20
= 80/20+ 3/20
= 83/20
The final answer is 83/20~
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