MATHEMATICS HIGH SCHOOL

The cosine of an angle is the ratio of the opposite side over the hypotenuse.a. True
b. False

Answers

Answer 1
Answer:

Answer:

False, The cosine of an angle is the ratio of the opposite side over the hypotenuse.

Let ΔABC is a right angled triangle, ∠C = 90°

Figure is attached.

let ∠B be \theta

Then the trigonometric ratios are the following:

sin\,\theta=(AC)/(AB)

cos\,\theta=(CB)/(AB)

tan\,\theta=(AC)/(CB)

cosec\,\theta=(AB)/(AC)

sec\,\theta=(AB)/(CB)

tan\,\theta=(CB)/(AC)

So, clearly cos\,\theta=(Adjacent)/(Hypotenuse)

Its sin\,\theta=(Opposite)/(Hypotenuse)
Answer 2
Answer: It's False.Sine is a trigonometric function of the angle in a right triangle is equal to the ratio of the opposite leg to the angle of the hypotenuse.

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Tomika plans to run 84miles in 4weeks.If she continues the pattern how many miles will she run in a year

Answers

Answer:

She will run a distance of 1095.78 miles per year.

Explanation:

 Number of days in a year = 365.25

 Number of days in a week = 7

 Number of weeks in a year = 365.25/7 = 52.18 weeks.

 Tomika plans to run 84 miles in 4 weeks.

 Distance run by Tomika in 1 week = 84/4 = 21 miles.

 Distance run by Tomika in 1 year = 21*52.18 = 1095.78 miles

 So she will run a distance of 1095.78 miles per year.

If Tomika continues the pattern, she will run approximately 1,092 miles in a year.

How to get the miles ran

There are 52 weeks in a year, so you can divide 52 by 4 to find out how many 4-week periods there are in a year:

Number of 4-week periods in a year = 52 weeks / 4 weeks/period = 13 periods

Now, multiply the miles she runs in each 4-week period (84 miles) by the number of 4-week periods in a year (13 periods):

Total miles in a year = 84 miles/period × 13 periods

Total miles in a year = 1,092 miles

So, if Tomika continues the pattern, she will run approximately 1,092 miles in a year.

Read more on pattern here  brainly.com/question/28580633

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Endpoints of major axis at (0,6) and (0,-6) endpoints of minor axis at (-3,0) and (3,0)

Answers

we can see that the center is (0,0)

and from commments we know tat it is ellipse

since major axis is y direction ( and center (0,0)), it is a vertical ellipse
in form
(x^(2))/(b^(2)) + (y^(2))/(a^(2)) =1

where a is the distance from the center to major axis end
b is distance of minor axis
and a>b always for ellipse

from (0,0) to (0,6) is 6 units, major axis
from (0,0) to (3,0) is 3 units, minor axis

(x^(2))/(3^(2)) + (y^(2))/(6^(2)) =1

a ball is dropped from a height of 100 inches the ball bounces, each time reaching a lower and lower height. the height of each bounce is 75% of the previous bounce what height will the ball reach after bouncing four time? how many bounces does it take for the ball to reach a heigh of less than one inch?

Answers


After the 'n'th bounce, the ball returns to a maximum height of

               (100) times (0.75)^n .

-- After 4 bounces, the maximum height is (100) (0.75)^4 = 31.64 inches.

-- To look for the maximum height of 1 inch,     (100) (0.75)^x = 1

Let's take the log of each side:    log(100) + x log(0.75) = 0

Subtract  log(100)  from each side:      x log(0.75) = -log(100)

Divide each side by  log(0.75) :            x  =  -log(100) / log(0.75).

log(100) = 2 .  So ...    x = -2 / log(0.75)  =  -2 / -0.124939  =  16.00785    

So the ball returns to a slim hair more than 1 inch high on the 16th bounce,
and returns to definitely less than 1 inch high on the 17th bounce.


What is the value of the expression |-20 + 5|?

Answers

I THINK IT'S 15. you do the addition first then do the absolute value 

Horce read 160 pages in 4 hours. how many pages can he read in 6hours

Answers

Steps:
1. Do a proportion
160 pages/ 4 hours= x/ 6 hours
2. Do 160 times 6 which equals 960
3. Do 960 divided by 4 which equals 240
4. Your answer is
240 pages
let x be the amount of pages
160/4=x/6
4x=960 (cross multiplied)
x=240 (divided by 4 to both sides)

therefore 240 pages in 6 hours

What is the answer to this?

Answers

Answer:

-3

Step-by-step explanation:

Step 1: Define

∛(-b² + a)

a = -2

b = 5

Step 2: Substitute

∛[-(5)² + (-2)]

Step 3: Evaluate

∛(-25 - 2)

∛-27

-3
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