Which one is greater 0.6 or 0.60

Answers

Answer 1
Answer: They are the same, because there's an invisible 0 next to 0.6.....
Answer 2
Answer: .6 and .60 are equal in the same way that 60 and 060 are equal -- The 0 is useless. More mathematically, .6 = six tenths or 6/10 and .60 = sixty hundredths or 60/100 and 6/10 is just a simplified version of 60/100.

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How do I solve forax+by=c​

Answers

Answer:

Subtract ax from both sides. ax + by − ax = c − ax.

Simplify. by = c − ax.

Divide both sides by b ; b ≠ 0. by b = c b − ax b ; b ≠ 0.

Simplify. y = c − ax b ; b ≠ 0.

Which is bigger 5200ft 145in or 1mi 40in

Answers

5200ft 145in is less than 1mi 40in because 1mi 40in is equal to 5283.33 ft 

Any smart people out there, i really suck at these problems... Five times Lauren's age, decreased by 2 is equal to two times Lauren's age, increased by 11. How old is Lauren?

Answers

Set Lauren's age equal to L.


Using what the problem gave us, we can quickly set up an equation: 

5L - 2 = 2L

Solving this equation, we get 3L = 2. L = 2/3 Lauren is 2/3 of a year old.

Take it slowly, one step at a time.

First, you need to pick something to call "Lauren's age",
because you don't know what number it is.  I have a bright idea ! 
Let's call Lauren's age ' L ' !  OK ?

Use ' L ' to build the quantities discussed in the question:

Five times Lauren's age . . . . . . . . . . . . . . . . . 5 L
Five times Lauren's age, decreased by 2 . . . 5L - 2

Two times Lauren's age . . . . . . . . . . . . . . . . .  2 L
Two times Lauren's age, increased by 11 . . . 2L + 11

The question says that these 2 quantities are equal,
so write that down:
                                                      5L - 2  =  2L + 11

Add  2  to each side:                  5L        =  2L + 13

Subtract  2L  from each side:    3L        =           13

Divide each side by  3 :                L        =           13/3  or  4 and 1/3 .

That's certainly a weird number, but you can
check it out, and you'll find that it's true:

Lauren's age . . . . . 13/3

Five times Lauren's age . . . . . . . . . . . . . . . . . 65/3
Five times Lauren's age, decreased by 2 . . . 59/3    <===

Two times Lauren's age . . . . . . . . . . . . . . . . .  26/3
Two times Lauren's age, increased by 11 . . . 59/3    <===

Those 2 quantities are equal.  So Lauren is 4-1/3 years old, by golly !

On average shawnte drinks 1/2 of a 6-ounce glass of water in 2/3 hour how much watee does she drink in a hour

Answers

she drinks 9/2 ounces of water in 1 hour

Step-by-step explanation:

On average, the person drinks 1/2 of a 6-ounce glass of water in 2/3 hour.

First of all, we have to rewrite the amount of water in a single fraction: we have

(1)/(2)\cdot 6 = (6)/(2)=3

This means that the person drinks 3 ounces of water every 2/3 hours.

In order to find how much water she drinks in one hour, we use the following proportion:

(3)/(2/3)=(x)/(1)

where

x is the amount of water she drinks in one hour.

Solving the equation for x,

x=(3\cdot 1)/(2/3)=(3\cdot 1 \cdot 3)/(2)=(9)/(2)

Therefore, she drinks 9/2 ounces of water in 1 hour.

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

#LearnwithBrainly

The sum of a number ,1/6 of that number ,2 1/2 of that number, and 7 is 2 1/2 find the number

Answers


Let x be the number. If I understand the wording of the problem correctly, then the equation is this:  x + (1/6)x + (5/2)x + 7 = 5/2 .

x = - 27/22  or - 1 5/22 if a mixed number is desired.

Solve these system of linear equations:5x-y=10}
4x-2y=20}

AND:

3x+4y=12}
2x-y=-10}

WITH STEPS PLEASE!!!!!

Answers

5x-y=10 \n4x-2y=20 \ \ \ |\hbox{divide both sides by (-2)} \n \n5x-y=10 \n\underline{-2x+y=-10} \ \ \ |\hbox{add by sides} \n5x-2x-y+y=10-10 \n3x=0 \nx=0 \n \n\hbox{substitute 0 for x in one of the equations:} \n5 * 0 -y=10 \n-y=10 \ny=-10 \n \n\hbox{the answer:} \nx=0 \n y=-10



3x+4y=12 \n2x-y=-10 \ \ \ |\hbox{multiply both sides by 4} \n \n3x+4y=12 \n\underline{8x-4y=-40} \ \ \ |\hbox{add by sides} \n 3x+8x+4y-4y=12-40 \n11x=-28 \nx=-(28)/(11) \nx=-2 (6)/(11) \n \n\hbox{substitute -28/11 for x in one of the equations:} \n2 * (-(28)/(11))-y=-10 \n-(56)/(11)-y=-(110)/(11) \n-y=-(110)/(11)+(56)/(11) \n-y=-(54)/(11) \ny=(54)/(11) \ny=4 (10)/(11) \n \n\hbox{the answer:} \nx=-2(6)/(11) \ny=4 (10)/(11)