What is the taste of the resulting mixture?
Answers
The taste of the resulting mixture depends on the constituents of the mixture. The amount of the constituents of the mixture also plays a vital role in determining the taste of the mixture.
Further Explanation:
The mixture is a composition of two or more different types of compounds or entities mixed in a desired ratio in order to obtain a different product as a result of the two quantities. The mixing of two or more entities is called as a mixture only when there is no chemical reaction taking place between the two entities.
The taste of a mixture depends on the quantity of the compounds mixed in the formation of the mixture. If we consider the example of the mixture of glucose and water, the sweetness of the mixture depends on the amount of glucose added to the water. The more the amount of glucose, more will be the sweetness of the solution.
In the same manner, in the solution of salt and water, the taste of the mixture depends on the amount of salt added to the water.
Therefore, it can be stated that the taste of the mixture is dependent on the amount of the compound used in the formation of the mixture.
Learn more:
1. Wind and solar energy are examples of brainly.com/question/1062501
2. Water is a compound because it brainly.com/question/4636675
3. The component of a level brainly.com/question/1073452
Answer Details:
Grade: Junior School
Subject: Physics
Chapter: Mixtures
Keywords:
Mixture, entities, compounds, taste, sweet, sugar and water, glucose and water, salt and water, amount, composition, chemical.
The taste of the resulting mixture depends upon the ingredients and constituents.
The particular ingredients being blended will determine the flavor of the finished product. When combined, different components can have contrasting flavors and produce a distinctive flavor profile.
Sweet: A mixture that contains sugar, honey, or other sweet substances is likely to taste sweet.
Salty: Adding salt, soy sauce, or salty seasonings will make a dish taste salty.
Sour: When sour flavors, such as vinegar or lemon juice, are combined with other substances, the result is a sour flavor.
Spicy: When combining hot or spicy ingredients, such as chili peppers or hot sauces, the mixture will taste hot or spicy.
Bitter: When combined with other ingredients, some items, such as bitter melon or greens like kale, can add to the bitterness of the dish.
Hence, the taste of the resulting mixture depends upon the ingredients.
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Answers
Answer:
The hottest objects with temperatures in the millions of Kelvins, give off most of their radiation in the form of X-rays and gamma rays.
Explanation:
The electromagnetic (EM) spectrum contains radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays and gamma-rays. All these different types of radiation are made up of photons having specific wavelengths and different amounts of energy. In the EM spectrum, the photons of radio waves have the lowest energy and the energy of photons increases through microwaves, infrared, visible light, ultraviolet, X-rays, and the photons of gamma-rays have the highest energy (the energy of photons is measured in electron volts).
All warmer objects such as stars, planets, etc emit photons having a specific range of wavelengths and it depends on the surface temperature of those objects. The very hot objects with temperatures in the millions of Kelvins or more mainly emit photons with shorter wavelengths, such as gamma rays and X-rays while cooler objects emit radiation such as infrared or radio waves, having longer wavelengths.
The ultraviolet radiation has the energy in the range of a few electron volts to about 100 eV. The energy of X-ray photons is in the range of 100 eV to 100 keV and the energy of gamma-rays is greater than 100 keV. The nuclear explosions, radioactive decay, the hottest and most energetic objects in the universe such as neutron stars, supernova explosions, etc produce gamma rays.
Objects with temperatures in the millions of Kelvins emit most of their radiation in the X-ray and gamma-ray parts of the electromagnetic spectrum.
Objects with temperatures in the millions of Kelvins primarily give off most of their radiation in the X-ray and gamma-ray parts of the electromagnetic spectrum. As an object's temperature increases, the wavelengths of radiation it emits become shorter. This phenomenon is described by Wien's displacement law.
At lower temperatures, such as those found on Earth or in stars like our Sun, objects emit most of their radiation in the visible and infrared parts of the spectrum. However, as temperatures rise to millions of Kelvins, the emitted radiation shifts to shorter wavelengths, eventually falling into the X-ray and gamma-ray regions.
In the X-ray and gamma-ray parts of the electromagnetic spectrum, radiation has extremely high energy and short wavelengths. These types of radiation are associated with the very high temperatures and intense energy found in extremely hot objects, such as the cores of massive stars, supernovae, and certain high-energy astrophysical phenomena. Scientists use X-ray and gamma-ray telescopes to study these extreme environments and the radiation they emit.
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Answers
Answer:4500 N
Explanation:
Given
mass of truck
mass of car
as the car push the ground with a force of 4500 N so the force on the truck should also be 4500 N as they all the force is transmitted to push the truck
and their acceleration is
Final answer:
Based on Newton's third law of motion, if the car is pushing against the ground with a force of 4500N, that same force is what propels the car and any object attached to it, regardless of the object's mass. Therefore, the car also applies a force of 4500N to the truck it is pushing.
Explanation:
The magnitude of force that a 1200-kg car applies to a 2100-kg truck with a dead battery can be calculated using the principles of Newtons's third law of motion which states that for every action there is an equal and opposite reaction. The force exerted by the car on the ground is equal to the force exerted by the ground on the vehicle. If the car's driving force against the ground is 4500N, as per Newton's third law, the ground also pushes the car back with the same force of 4500N. This force is what propels the car and any object it's connected with.
So, when the car is pushing this truck, it applies this same force of 4500N to the truck. Therefore, the magnitude of force the car applies to the truck is 4500N.
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Answers
The clay must be 300 m/s fast in other to stop the car.
For the car to stop, The momentum of the car must be equal to the momentum of the clay.
Formula:
- MV = mv................. Equation 1
Where:
- M = mass of the car
- V = Velocity of the car
- m = mass of the clay
- v = velocity of the clay
Make v the subject of the equation.
- v = MV/m................... Equation 2
From the question,
Given:
- M = 1500 kg
- V = 2 m/s
- m = 10 kg
Substitute these values into equation 2
- v = 1500(2)/10
- v = 300 m/s.
Hence, The clay must be 300 m/s fast in other to stop the car.
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Final answer:
To stop the car rolling at 2.0 m/s with a blob of clay, you should fire the blob of clay at a speed of 300 m/s. This is based on the principle of conservation of momentum.
Explanation:
The question involves a principle of Physics called the law of conservation of momentum. The law states that the total momentum of a system remains constant if no external forces act on it. Here, the car and the clay are the two objects in the system.
At the start, only the car has momentum, which can be calculated with the equation: momentum = mass x velocity => momentum of car = 1500 kg x 2 m/s = 3000 kg m/s.
After the clay is fired at the car, the total momentum of the system (car + clay) still remains 3000 kg m/s, but now the momentum is shared between them. We want to stop the car, so it will now have no momentum, meaning all momentum must be with the clay.
The equation again turns to momentum = mass x velocity => velocity = momentum/mass => velocity of clay = 3000 kg m/s / 10 kg = 300 m/s.
You should fire the clay at 300 m/s to stop the car.
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Answers
Answer:
second class lever
Explanation:
Answers
Answer:
To calculate the percentage of l-131 that has decayed up to the year 2021, we need to determine how many half-lives have passed from 1959 to 2021 and then calculate the remaining percentage.
The half-life of l-131 is 8.02 days.
First, calculate the number of half-lives that have passed from 1959 to 2021:
Number of years = 2021 - 1959 = 62 years
Since each year has approximately 365 days:
Number of days = 62 years * 365 days/year = 22,630 days
Now, calculate the number of half-lives:
Number of half-lives = Number of days / Half-life = 22,630 days / 8.02 days/half-life ≈ 2822 half-lives
Now, we know that each half-life reduces the remaining amount to half. So, to calculate the percentage remaining after 2822 half-lives:
Percentage remaining = (1/2)^2822 * 100 ≈ 0%
So, approximately 0% of the initial l-131 has decayed up to the year 2021.
b. Plate tectonics caused lava to flow.
c. Earth and a planetesimal collided.
d. The lunar surface melted and was bombarded by meteoroids
Answers
There are 5 serious theories about the formation of the moon,these are:
The Fission Theory--
The Capture Theory--
The Condensation Theory--
The Colliding Planetesimals Theory--
The Ejected Ring Theory--
See attached file for the description of each theory.