The cars coupled and rolled together at a speed of 1.5 m/s.
According to the law of conservation of linear momentum, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided objects, u₁ and u₂ are their initial speed while v₁ & v₂ is their final speed.
The linear momentum of an object can be defined as the product of the mass of the object times the velocity of that object. Conservation of momentum is a property held by an object where the total amount of momentum never changes.
Given the initial velocity of the car is u₁ = 2 m/s and the other car is u₂ = 1 m/s.
The masses of both cars is identical, m₁ = m₂ = m
From the law of conservation of momentum, find the speed of coupled cars (v),
m₁ u₁ + m₂ u₂ =m₁ v₁ + m₂v₂
m × 2 + m ×1 = m × v + m × v
2 + 1 = 2 v
2v = 3
v = 1.5 m/s
Therefore, the speed of the coupled cars is equal to 1.5 m/s.
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B. color.
C. wave nature.
D. particle nature.
The electric potential difference is the electric potential energy per unit charge
Explanation:
First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance from a positive charge of magnitude is given by
where k is the Coulomb's constant.
Now we can define the electric potential energy and the electric potential difference:
The electric potential energy is also defined as the work done on a charge q moved through a potential difference of . Consequently, the potential difference represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference .
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