A recent survey found that 79% of Americans use the internet. if a city has a population of 76,000 how many people in that city would you expect to use the internet?

Answers

Answer 1
Answer: p\%=(p)/(100)\n\n79\%=(79)/(100)=0.79\n\n79\%\ of\ 76,000\ is\ 0.79\ *\ 76,000=60,040\leftarrow answer
Answer 2
Answer: 79 % of 76 000 ?

79 % = 79/100 = 0.79

So 0.79 * 76 000 = 60 040

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To solve 5y - 2 - 3y=8, can you start by adding 2 each side? Justify your reasoning.

Answers

Yes, you can start by adding 2 to each side, it doesn't made a difference if you combine 5y and -3y first or not. Either way, you still get y= 5 both ways you do it.
yes , you can add the 2 to both sides. you are combining like terms. it would be easier if you start off by doing 5y - 3y = 2y so the new problem would ne 2y-2=8 then add the 2 so 2y=10 so y = 5.

A certain forest covers an area of 2,000 square kilometers. Suppose that each year this area decreases by 6%. What is the function that bestrepresents the area of the forest each year and how much area remains after 12 years? Round your answer to the nearest square kilometer.Hint: Use the formula, f(x) = P(1 + r)x.

Answers


The question gives you the formula to use, but it's printed wrong.
The 'x' is an exponent after the (1 + r).

All you have to do is take the formula, and write the numbers into it
that are also given.

The key thing to spot is that the forest is decreasing, so the 'r' is negative,
just as if you had money in a savings account and every year the bank took
6% out of it.

So the formula to use is       f(x)  =  P (1 + r) ^x

P = 2000
r = -0.06
                        f(x)  =  2000 (1 - 0.06)^x
                               =  2000 (0.94)^x

The amount left after 12 years is
        
                                   2000 (0.94)¹² =

                                   2000 (0.476)  =  951.8 square kilometers.
                  

hope this helps- i did the test :)

Answer:

The cost C, in dollars, of building m sewing machines at Sienna’s Sewing Machines is given by the equation: C(m) = 20m^2 - 830m + 15,000
(a) Find the cost of building 75 sewing machines.
(b) How many sewing machines should the company manufacture
to minimize the cost C?

Answers


OK.  So the cost to manufacture any number 'm' machines is

                               C(m) = 20m^2 - 830m + 15,000 .

Whatever number of machines you're interested in, you write
that number in place of 'm', and this equation tells you the cost
for that many.

Examples:

-- The cost to manufacture zero sewing machines ... what the
company had to invest in equipment and building space before
they could even start manufacturing anything:

                   
C(m) = 20m^2 - 830m + 15,000

                    C(0)  =  20(0)²  -  830(0)  +  15,000  =  15,000 .

-- The cost to manufacture one sewing machine ... buy the
building, set up the manufacturing equipment, and turn out
the first one:

                     
C(m) = 20m^2 - 830m + 15,000

                      C(1)  =  20(1)²  -  830(1)  +  15,000  =  14,190 .

Now, part-a) wants to know the cost to build 75 sewing machines. 
If you've been paying attention so far, you know you have to take
the same equation, and write '75' in place of 'm'.

                      
C(m)  =  20m^2  -  830m  +  15,000

                       C(75)  =  20(75)²  -  830(75)  +  15,000


                                   = 20(5,625) - 830(75) + 15,000

                                   = 112,500  -  62,250  +  15,000  =  65,250 .
===================

Now you need to find the number of sewing machines
that can be built for the lowest total cost.

I'm sure you noticed that the equation for the cost  C(m)  is a
quadratic equation.  So if you drew it on a graph, it would be
a parabola.  It would have a minimum value at some 'm', and
for greater 'm', it would start going up again.
 
(Why should your cost start increasing past some number of
sewing machines ?  Well, maybe the manufacturing equipment
is starting to wear out, and needs repair more often.
  All of that
is actually built into the equation for C(m) . )

Now, I'm not sure what method you've learned for finding the
minimum value of a parabola (quadratic equation).  Here are
the two ways I know:

Way #1).  If you've had some pre-calculus, then you'll take the
derivative of the equation, set the derivative equal to zero, and
that leads you to the minimum:

The equation:                C(m) = 20m^2 - 830m + 15,000

Its first derivative:          C'(m) = 40m - 830

'C'; is minimum when C'=0 :      40m - 830 = 0

Add 830 to each side:                40m          = 830

Divide each side by  40 :                m          = 20.75

The number of sewing machines manufactured for the
minimum total cost is  20  or  21 .

Way #2).  Really the same as Way-#1 but it's not called 'derivative'.

I looked online for rules of parabolas, and found the one that
you may have learned to use:

       For the quadratic expression    Ax² + Bx + C ,
       the axis (midline) of the parabola is at
                                                                           x = - B / 2A .

That's exactly what we need.
Our equation is                            C(m) = 20m^2 - 830m + 15,000

so the axis of the parabola is at        =  - (-830)/2(20)

                                                                   =      830/40  =  20.75 .

Same as Way-1 .
so basically function of m (f(m) or in this case C(m)) means the price
so just input the value you put for m for all the other m's in the problem
ex. if you had f(x)=3x and you wanted to find f(4) then you replace and do f(3)=3(4)=12 so f(3)=12 and so on



A. cost of 75 sewing machines
75 is the number you replace m with
C(75)=20(75)^2-830(75)+15,000
simplify
20(5625)-62250+15000
112500-47250
65250
the cost for 75 sewing machines is $65,250


B. we notice that in the equation, that the only negative is -830m
so we want anumber that will be big enough to make -830m destroy as much of the other posities a possible

-830m+20m^2+15000
try to get a number that when multiplied by 830, is almost the same amount as or slightly smaller than 20m2+15000 so we do this
830m<20m^2+15000
subtract 830m from both sides
0<20m^2-830m+15000
factor using the quadratic equation which is
(-b+ the square root of (b^2-4ac))/(2a) or (-b- the square root of (b^2-4ac))/(2a)
in 0=ax^2+bx+c so subsitute 20 for a and -830 for b and 15000 for c
you will get a non-real result I give up on this meathod since it gives some non real numbers so just guess

after guessing and subsituting, I found that the optimal number was 21 sewing machines at a cost of 6420

How to rewite this x+4y=-4 in form y=mx+b

Answers

x+4y=-4\n4y=-x-4\ny=-(1)/(4)x-1
so  if you want y=mx+b

you subtract x from both sides and get
4y=x-4
divide both sides by 4
y=(1/4)x-1 or y=(1/4)x+(-1)

3. Please help. Are lines ℓ and k parallel? Justify your response.

Answers

Answer:

No, lines  ℓ and k are not parallell because their slopes are not equal

No lines L and K are not parallel because they’re slope isn’t the same

The amount of time it takes to finish a race might be a function of which of the following?A.) the entry fee for the race
B. ) the number of people involved in the race
C.)the distance of the race

Answers

The correct answer is:

C) The distance of the race.

Explanation:

If one variable is written as a function of another, this means there is a relationship between the two variables.

There will be a relationship between the time it takes to finish a race and the distance of the race.  The longer the distance of a race is, the more time it will take to finish it.  Therefore the time can be written as a function of the distance.
The correct answer is C. The distance of the race

The entry fee and the number of people involved can have no influence on the amount of time it takes to finish it.
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