Thomas is planning a trip to India. He is currently deciding which cities he would like to visit during his stay. The table below shows possible cities for Thomas to visit, as well as how much money he expects to need at each one. All costs are given in Indian rupees (Rs.). City
Cost (Rs.)
Jaipur
6,920
Mumbai
9,464
Thiruvananthapuram
9,160
Lucknow
5,276
Bhopal
8,268
Bhubaneswar
7,109
New Delhi
6,303
Bengaluru
6,735

Thomas had originally planned to visit Thiruvananthapuram, Mumbai, Bhubaneswar, and Bengaluru, but his budget of Rs. 25,300 makes that impossible. Which of the following itinerary changes will allow Thomas to stay within his budget? (Consider each option individually, rather than as a group.)

I. Swap Thiruvananthapuram for Jaipur and drop Bengaluru.
II. Drop Bhubaneswar.
III. Swap Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.
a.
I and II
b.
III only
c.
I and III
d.
I, II, and III

Answers

Answer 1

Answer:

The itinerary changes that will allow Thomas to stay within his budget is C. I and III. Check how to reach the result below.

What is a budget?

It should be noted that a budget simply means an estimate of the income and expenditure of an individual.

In this case, the itinerary changes that will allow Thomas to stay within his budget include swapping Thiruvananthapuram for Jaipur and drop Bengaluru and swapping Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.

In this case, a trip to Mumbai costs

9,464 while a trip to New Delhi is 6,303. Therefore, a trip to New Delhi is better in this scenario as it more budget friendly.

Learn more about budget on:

brainly.com/question/6663636

Answer 2

Answer: Swap Thiruvananthapuram for Jaipur and drop Bengaluru and Swap Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.this option is cheaper for thomas

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Simplify by factorising first

Answers

Answer:

x+8

Step-by-step explanation:

Simplify the numerator

list the factors of 16

16: 1, 2, 4, 8, 16

look for two factors that add up to the b value

in this case it is 18

by looking at the factors 2 and 8 add up 10

so you can rewrite the numerator as $x^(2)+2x+8x+16$

Split the trinomial into two separate binomials each having one of the factors that add up to 10

So it should be $x^(2) +2x and 8x+16$

Factor both binomials

you can factor an x from the first one

Then it is x(x+2)

Factor an 8 from the second one

8(x+2)

So it should be $x(x+2) 8(x+2)$

This can rewritten as (x+8)(x+2)

So now you have $((x+2)(x+8))/(x+2))$

simplify it by canceling out the two (x+2)'s

this is because (x+2)/(x+2) is 1

Finally you get x+8

Which point in a triangle is equidistant from the vertices of the triangle?

Answers

Since a point equidistant from two points lies on the perpendicular bisector of the segment determined by the two points, the circumcenter (labeled below) is the point of concurrency of the three perpendicular bisectors of each side of the triangle.

Answer: The point of intersection of the perpendicular bisectors. On plato its C.

Jeremy wants to buy a new computer. The saleswoman says that he can make a down payment and then pay for the computer in installments.Here's a formula that describes this scenario:

x=t-yz

x = Amount down
y = Money each month
z = Number of months
t = Total price

Rewrite the formula to solve for the amount of money Jeremy must pay each month.

Answers

Answer: $y=(t-x)/(z)$

Step-by-step explanation:

Given: A formula that describes this scenario:

$x=t-yz$

where, x = Amount down

y = Money each month

z = Number of months

t = Total price

To solve the formula for the amount of money Jeremy must pay each month i.e. y, first subtract t on both sides of the equation, we get,

$x-t=-yz\n\n\Rightarrow\ yz=t-x$

Now, divide z on both sides, we get

$y=(t-x)/(z)$

The correct answer is:

$y=(-x+t)/(z)$

Explanation:

We want to solve for the amount of money he pays each month. This is represented by y in the equation. This means we want to isolate y in the equation:

x = t - yz

We first want to subtract t from each side:

x - t = t - yz - t

x - t = -yz

Now we want to cancel the negative sign and z. We can isolate both of these at the same time; divide both sides by -z: