MATHEMATICS MIDDLE SCHOOL

How many milliliters if soda does a 2 liter bottle hold show work

Answers

Answer 1

Answer: 2 liters x (1000 ml / 1 liter ) = 2000 ml

Answer 2

Answer:

Answer:

Step-by-step explanation:

How many milliliters are in a 2 liter bottle of soda?

500 mL

There are 500 mL in 1/2 liter.

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Which is the equation of a line that has a slope of 1/2 and passes through point (2, -3)?

Tyler is thinking of a number that is divisible by 2 and by 3. By which of the following numbers must Tyler's number also be divisible?

Answers

Tyler's number also divisible of multiples of 6.

What is division?

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.

Given:

Tyler is thinking of a number that is divisible by 2 and by 3.

Co-prime numbers include the numbers 2 and 3.

As a result, if a number can be divided by 2 and 3,

it must also be divided by their product, or 6, which is 6.

All the multiples of 6 can be divided by 2 and 3.

Therefore, all the multiples of 6 can be divided by 2 and 3.

To learn more about the division;

brainly.com/question/13263114

#SPJ5

6,12,24 are numbers that are divisible by 2 and 3.

A rectangular blanket's perimeter is 210 inches. If the long sides of the blanket measure 60 inches, what is the length of the shorter sides of the blanket?

Answers

perimeter is going to be figured by using 2L + 2W

2(60) +2W = 210
120 +2W = 210
-120 -120

2W = 90
divde by 2 on both sides

W = 45

Length of the shorter sides are 45 inches.

The lengh of the shorter sides is 45 inches

Round 4398202 to nearest hundred

Answers

4398200

round 202 to 200 :)
If you need more help message me so you don't use your points!

Wouldn't be 4398200 because you are just rounding it to the bearest HUNDRED????

How do you do these problems? And is the first one done right?

Answers

the volume of a right-circular cylinder is V = πr²h, however, this cylinder on 6) is not a right-circular cylinder, meaning, the its altitude is not going straight up making a right-angle with the ground, is all slanted.

now, let's recall Cavalieri's Principle,

solids with the same altitude and cross-sectional areas at each height have the same volume.

so, though this cylinder is slanted, its cross-sectional areas are the same as a right-circular cylinder and thus its volume is also V = πr²h, so yes, is correct.

the area of a parallelogram is A = bh.

so the volume of this solid will simply be the area of the upfront parallelogram times the depth or length of 5x.

$\bf (4x)(x+2)(5x)\implies (20x^2)(x+2)\implies 20x^3+40x^2$

I need help please quick. Is 69 is answer?

Answers

Answer:

Yes.

Step-by-step explanation:

1973 - 1904 = 69

Answer:

1973-1904=69

Explanation:

1973-69=1904

1904+69=1973

PLSSSS HELP ITS DUE TODAY!!!!!

Answers

Answer:

Both Jules' and Lauren's equations are correct because they have slopes that are the negative reciprocal of the slope of the given line, making them perpendicular to the given line.

Step-by-step explanation:

Let's reevaluate the equations based on the corrected given line equation:

$\sf y - 2 = (1)/(5)(x - 3)$

The given line equation is in point-slope form: $\sf \boxed{\sf y - y_1 = m(x - x_1)}$ , where m is the slope.

Given line equation: $\sf y - 2 = (1)/(5)(x - 3)$

While comparing, we get

$\textsf{The\underline{ slope (m) }of the given line is }(1)/(5)$

For a line to be perpendicular to the given line, its slope must be the negative reciprocal of the slope of the given line.

The negative reciprocal of $\sf (1)/(5)$ is $\sf -5.$

Now let's check the slopes of the equations provided by Jules and Lauren:

1. Jules' equation: $\sf y = -5x + 1$

The slope of Jules' equation is -5, which matches the negative reciprocal of the slope of the given line.

2. Lauren's equation: $\sf y = -5x + 7$

The slope of Lauren's equation is also -5, which again matches the negative reciprocal of the slope of the given line.

Both Jules' and Lauren's equations have a slope of -5, which is the negative reciprocal of the slope of the given line $(1)/(5)$ .

Therefore, both equations are correct and satisfy the condition of being perpendicular to the given line $\sf y - 2 = (1)/(5)(x - 3)$

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$y-2=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{5}}(x-3)\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\n \cline{1-1} \n y-y_1=m(x-x_1) \n\n \cline{1-1} \end{array} \n\n[-0.35em] ~\dotfill$

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{1}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{1} \implies -5}}$

so ANY line that is perpendicular to that equation above, will have a slope of -5, so any of these are all perpendicular to it

$\begin{array}{llll} \stackrel{ Jules }{y=-5x+1} \n\n\n \stackrel{ Lauren }{y=-5x+7} \n\n\n y=-5x+999999999 \n\n\n y=-5x-93789 \end{array}\hspace{5em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\n \cline{1-1} \n y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \n\n \cline{1-1} \end{array}$

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