Answer:
Step-by-step explanation:
Using the formula for calculating the distance between two points as shown;
D = √(x2-x1)²²+(y2-y1)²
Given the coordinates (-2, 4) and (10,2)
x1 = -2, y1 = 4, x2 = 10 and y2 = 2
substitute into the formula;
D = √(10+2)²+(2-4)²
D = √(12²+(-2)²
D = √144+4
D = √148
D = 12.17 units
Hence the distance of Mac,s house from Nate's house is 12.17 units
To find the coordinates of Mac's house, we use the section formula in mathematics. By substitifying the given locations of Nate's house and the park into the formula, we conclude that Mac's house is located at approximately (2, 3.33) which is one third the distance from Nate's house to the park.
In this math problem, we are dealing with points in a 2D cartesian coordinate system. Nate's house is at (-2, 4) and the park is at (10, 2). Mac's house is located one third of the distance between these two points. Following the formula for the coordinates of a point dividing a line segment in a given ratio, we can find Mac's house location.
Let the coordinates of Mac's house be (x, y). We use the formula for section formula which is:
x = [(m*x2 + n*x1) / (m+n)] and y = [(m*y2 + n*y1) / (m+n)]
Here, x1, y1 (-2, 4) are the coordinates of Nate's house, x2, y2 (10, 2) are the coordinates of the park and the ratio m:n is 1:2 since it's one third of the distance from Nate's house to the park.
By substituting these values in the formula, we get x = [(1*10 + 2*-2) / (1+2)] = 2 and y = [(1*2 + 2*4) / (1+2)] = 3.33
So, the coordinates of Mac's house are approximately (2, 3.33).
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Answer:
THE ANSWER IS F. 23!
Step-by-step explanation:
THE ANSWER IS F. 23!
Answer:
10 in
Step-by-step explanation:
We are given that
Diameter of cactus=d=12 in
Radius of cactus=
Distance of lizard from point of tangency=8 in
We have to find the direct distance between lizard and cactus.
In triangle OAB,
OA=6 in
AB=8 in
Pythagorous theorem:
Using pythagorous theorem
Hence, the direct distance of lizard from cactus=10 in