F (x)= 5x-14 G (x)= 12x+8 H (x)= 62x-54 Dadas las funciones resolver las siguientes operaciones a. F (x)+ G (x) b. G (x)- (H (x)-F (x)) c. (G (x)-F (x)) (H (x)+G (x) d. (F (x)-H (x))/ (G (x)+ F(x) e. G (x) / H (x9

Answers

Answer 1
Answer:

Answer:

a)17\cdot x -6, b)-45\cdot x +48, c)518\cdot x^(2) +1306\cdot x -1012, d)(-57\cdot x +40)/(17\cdot x -6), e)2\cdot \left((3\cdot x + 2)/(31\cdot x - 27) \right)

Step-by-step explanation:

Sean f(x) = 5\cdot x -14, g(x) = 12\cdot x + 8 y h(x) = 62\cdot x - 54. A continuación, desarrollamos las siguientes operaciones:

a)f(x) + g(x)

(5\cdot x - 14) + (12\cdot x + 8)

17\cdot x -6

b)g(x) - [h(x)-f(x)]

(12\cdot x + 8) - [(62\cdot x - 54)-(5\cdot x - 14)]

12\cdot x + 8 - (57\cdot x -40)

12\cdot x +8 -57\cdot x +40

-45\cdot x +48

c)[g(x)-f(x)]\cdot [h(x)+g(x)]

[(12\cdot x + 8)-(5\cdot x -14)]\cdot [(62\cdot x -54)+(12\cdot x +8)]

(12\cdot x +8 -5\cdot x +14) \cdot (62\cdot x -54+12\cdot x+8)

(7\cdot x +22)\cdot (74\cdot x-46)

7\cdot x \cdot (74\cdot x - 46)+22\cdot (74\cdot x -46)

(7\cdot x)\cdot (74\cdot x) - 46\cdot (7\cdot x )+22\cdot (74\cdot x)-22\cdot (46)

518\cdot x^(2)-322\cdot x +1628\cdot x -1012

518\cdot x^(2) +1306\cdot x -1012

d)(f(x)-h(x))/(g(x) + f(x) )

((5\cdot x - 14)-(62\cdot x - 54))/((12\cdot x +8)+(5\cdot x -14))

(-57\cdot x +40)/(17\cdot x -6)

e)(g(x))/(h(x))

(12\cdot x + 8)/(62\cdot x - 54)

(4\cdot (3\cdot x +2))/(2\cdot (31\cdot x -27))

2\cdot \left((3\cdot x + 2)/(31\cdot x - 27) \right)


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Answers

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What is the sum of 10 cubed and 25 squared?

Answers

The sum is 1625.

Answer in Words: One thousand and six hundred twenty-five.

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10 X 10 = 100 (square of ten)
100 x 10 = 1000 (cube of ten)

The square of 25 is 625.

25 x 25 = 625 (square of 25)

Therefore, 1000 + 625 = 1625

the sum is 1625

(2x raised to fourth power) raised to the negative fourth power

Answers

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\n \n =\frac { 1 }{ { \left( 2x \right)  }^( 16 ) } \n \n =\frac { 1 }{ { 2 }^( 16 ){ x }^( 16 ) } \n \n =\frac { 1 }{ 65536{ x }^( 16 ) }
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What is the domain of the function f (x) x-5/x^2-9

Answers

means the number you can use
remember we can't divide by zero
domain is x^2-9
set to zero to find values we can't use
x^2-9=0
x^2=9
x=+/-3

domain=all real numbers except -3 and 3

Find the sine, the cosine, and the tangent of the acute angles of the triangle. How to solve this? Thank you so much.

Answers

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the area of a rectangle is given by 6x²+19x+15. factor to find binomial that represent the length and width of the rectangle.​

Answers

Answer:Explanation:

Step-by-step explanation:Explanation:

We have that

6

x

2

+

19

x

+

15

=

6

x

2

+

10

x

+

9

x

+

15

=

2

x

(

3

x

+

5

)

+

3

(

3

x

+

5

)

=

(

2

x

+

3

)

(

3

x

+

5

)

Answer:

Step-by-step explanation:

6x² + 19 x +15 can be factor as (x-root1 )( x-root2)* coefficient of x²

use quadratic equation to fid the roots, x = (-b±√b²-4ac)/2a

6x² + 19 x +15 =0

x= (-19 ±√19²-4*6*15) / 2*6

x= (-19 ± √1)/ 12

x= (-19+ 1)/12 = -18/12 = -3/2

and

x= (-19-1)/12 = -20/12 = -5/3

6x² + 19 x +15 = 6*(x+(3/2)) (x+(5/3))

the length and with of the rectangle could be any combination of the factors of 6 and the (x+(3/2)) (x+(5/3))

if we consider 6 =2*3 we have length and width 2x+3 and 3x+5

because 2*[x+(3/2)]*3[ x+(5/3)]

if we consider 6 = 3*2 we have length and width 3x+(9/2) and 2x+(10/3)

because 3*[x+(3/2)]*2[ x+(5/3)]

if we consider 6= 6*1 we have length and width 6x+9 and x+(5/3)

because 6*[x+(3/2)]*1[ x+(5/3)]

if we consider 6= 1*6 we have length and width x+(3/2) and 6x+10

because 1*[x+(3/2)]*6[ x+(5/3)]