Write down a number you can square to give an answer bigger than 400 but smaller than 500

Answers

Answer 1
Answer: If you would like to know a number you can square and the answer is bigger than 400 but smaller than 500, you can calculate this using the following step:

20^2 = 400 < 21^2 = 441 < 22^2 = 484 < 500

There are two correct results: 21 and 22.

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How many grams of sodium chloride should be used in preparing 500 ml of a stock solution such that 50 ml?

Answers

Answer: 30 grams

Step-by-step explanation: (50 mL x x%) = (1000 mL x 0.3%)

x = 6%

6% x 500 mL = 30 grams

Final answer:

The calculation for the amount of sodium chloride (NaCl) in a solution depends on the desired concentration. For instance, to prepare 50 ml of a 1M solution, one would need 2.922 g of NaCl. For a 500 ml stock solution for the same, the measurement would be ten times this, or 29.22 g.

Explanation:

The question pertains to preparing a solution of sodium chloride N(aCl). The given information indicates that we have 5.30 mol NaCl L solution. To provide an accurate answer, it's necessary to know the targeted concentration for the 50 ml solution. However, lacking this data, we can consider an example where we want to prepare a 1M solution.

In such a case, using the concept of molarity (mol/L), we'd first establish how many moles of NaCl are needed. For a 1M solution, we'd need 1 mol of NaCl per liter of solution. Therefore, in order to prepare 50 ml (or 0.05 L), we require 0.05 mol of NaCl.

The given information also states that 1 mol of NaCl weighs 58.44 g. Therefore, we would need (0.05 mol) * (58.44 g/mol) = 2.922 g of NaCl for 50 ml of a 1M solution. Therefore, if preparing 500 ml of a stock solution, we would require 10 times this amount, or 29.22 g of NaCl.

This is a general guide as the specific quantity can vary based on the desired concentration of the 50 ml solution. For other concentrations, we would use the same method, simply adjusting the moles of NaCl needed as appropriate.

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Marco does 14 extra math problems each school night how many extra problems does he do each week. there are 5 school nights in a week

Answers

5 school nights* (14 math problems/ 1 school night)= 70 math problems.
(Note that the unit cancels out so you get the answer)

The final answer is 70 math problems~
Marco does 70 extra math problems each week. 14(5)=70 

Write the explicit formula for the geometric sequence. Then find the fifth term in the sequence. a1 = –4, a2 = 8, a3 = –16

Answers

The sequence:  a 1 = - 4,  a 2 = 8,  a 3 = -16,...
a 2 = a 1 * r
8 = - 4 * r
r = 8 : ( - 4 ) 
r = - 2
a n = a 1 * r^(n-1)
a 5 = - 4 * ( - 2 ) ^4 = - 4 * 16 = - 64
Answer:
The fifth term in the sequence is - 64. 

Answer:

B. an = –4 · (–2)n–1; –64

Step-by-step explanation:

Monica’s school band held a car wash to raise money for a trip to a parade in New York City. After washing 125 cars, they made $775 from a combination of $5.00 quick washes and $8.00 premium washes.This system of equations models the situation.

x + y =125

5x + 8y = 775

Solve the system to answer the questions.

How many premium car washes were ordered?

premium car washes



How many quick car washes were ordered?

quick car washes

Answers

Answer:

50 and 75

Step-by-step explanation:

trust me bro

Answer:

50 and 75

Step-by-step explanation:

Hope this helps :)

Darnell’s house was valued at $134,670 and it appreciated 3 percent per year. What is its value after 2 year? Round to the nearest dollar. A: $8,201 B:$142,871 C:$126,939 D:$277,541

Answers

Answer:

Option B is correct.

Step-by-step explanation:

Given: Value of House, P = $ 134,670

           Rate of depreciation, R = 3% per year

           Time, T = 2 years   ⇒ n = 2

To find: value of house after 2 year that is A.

We know that

A=P(1-(R)/(100))^n

A=134670(1+(3)/(100))^2

A=134670*1.0609

A = 142871.403

A = $ 142871

Therefore, Option B is correct.

134,670×(1+0.03)^(2)=142,871

Write and inequality for Toni can carry up to 18lb in her backpack.

Answers

X is less than or equal 18. I hope it helps