The table gives sales data for a stationery store in any given two weeks. It lists the probability of the number of items purchased in a single transaction and the average amount spent per transaction. Items Purchased in a Single Transaction Probability Average Amount Spent 2 0.35 $12 3 0.17 $20 4 0.33 $28 5 or more 0.15 $36 Based on the data provided, transactions with items are likely to bring in the most income during the next two-week transaction period.

Answers

Answer 1

Answer: From the given data:

Number of items | Probability of being purchased | Average amount spent
--------------------------------------------------------------------------------------------------
2 | 0.35 | $12
3 | 0.17 |    $20
4   | 0.33 | $28
5 or more   | 0.15 | $36

In a sample space of 100 items being purchased, in a day:

For 2 items: 35 (12) = 420
For 3 items: 17 (20) = 340
For 4 items: 33 (28) = 924
For 5 or more items: 15 (36) = 540

If this sample trend would go on the for the next two weeks, then the transaction with 4 items would most likely bring in the most income during the said transaction period.

Answer 2

Answer:

Answer:

Based on the data provided, transactions with 4 items are likely to bring in the most income during the next two-week transaction period.

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The assignment is about : Subtract Polynomials What i have to do : Subtract the polynomials, showing all the steps necessary to write the answer in simplest form. 1. (3x^1 + 8) - (2x^2 + 1)

2. (5x^2 + 3x - 4) (x^2 - 6x )

please show work

Answers

1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
3x^1 + 8 - 2x^2 - 1....now combine like terms
-2x^2 + 3x^1 + 7

2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
5x^2 + 3x - 4 - x^2 + 6x...combine like terms
4x^2 + 9x - 4

I keep getting different answers. Can somone explain how I would set it all up?

Answers

Answer:

MY=80

Step-by-step explanation:

MX=MY ( since M is the midpoint)

2x+10=3x-5

10+5=3x-2x

15=x

MX+MY=MX

2x+10+3x-5=MY

2(15)+10+3(15)-5=MY

MY=80

In a circle an arc length 10 is intercepted by a central angle of 2/3 radius

Answers

We have been given that in a circle an arc length 10 is intercepted by a central angle of 2/3. We are supposed to find the radius of the circle.

We will use arc-length formula to solve our given problem.

$l=r\theta$ , where,

$l$ = Arc length,

$r$ = Radius,

$\theta$ = Central angle corresponding to arc length.

Upon substituting our given values in arc-length formula, we will get:

$10=r\cdot (2)/(3)$

$10\cdot (3)/(2)=r\cdot (2)/(3)\cdot (3)/(2)$

$5\cdot (3)/(1)=r$

$15=r$

Therefore, the radius of the given circle would be 15 units.

Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16) A. y = x + 14
B. y = x – 6
C. y = x + 6
D. y = x

Answers

y = x + 8...slope here is 1. A parallel line will have the same slope.

y = mx + b
slope(m) = 1
(2,16)...x = 2 and y = 16
now we sub and find b, the y int
16 = 1(2) + b
16 = 2 + b
16 - 2 = b
14 = b

so ur parallel equation is : y = x + 14

The answer is A. y = x + 14

PLEQAEEEE HELPPP MEEE