What is the perimiter of a quadrilateral with verticles at (5,2), (10,2), (5,5), and (10,5)
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Answer:
55
Step-by-step explanation:
What is the number of birds per cubi yard for the aviary? with work please.
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for which number is the one you want to know
Which are natural numbers, integers, rational numbers, irrational numbers and real numbers?0, 1, 1/12, 1/16, 1/20
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-Natural numbers are 0+ (no negative or decimals) -Integers are any number that is not 0 or a fractional number (# with decimals/fractions) -irrational numbers are numbers with decimals that go on forever and that do not repeat themselves -rational number is any number that is predictable. So negative numbers, 0 and any number above 0 and decimals that are predictable (ex: 5.2) or any repeating decimal not decimals that goes on forever bu does not repeat them self for example π-real numbers are any digit that is rational. This includes negative numbers and fraction.
so to answer your question
0: Natural number, real number, rational 1: Natural number, Integer, real number, rational 1/12: real number, rational 1/16: real number, rational 1/120: Real number, rational
-Calypso, 8th
natural numbers are counting numbers (1,2,3,4,5...), not including 0
integers are natural numbers plus their negatives and zero (-3,-2,-1,0,1,2,3..)
rational numbers can be written in form a/b where b is not equal zero, terminating and repeating decimals can be written in this form
irrational numbers cannot be written in form a/b, they are non-terminating decimals
real numbers are rational+irrational numbers, not including imaginary numbers
basially natural numbers are in integers which are in rational numbers which are not integers and those make up real numbers
so
0 is a whole number but that wasn't listed so it is an integer, rational number and a real number
1 is a natural number, an integer, a ratioal number, and a real number
1/12 is in form a/b, so it is a rational number and a real number
1/16 is also in form a/b, so it is a rational number and a real number
1/20 is also in form a/b, so it is a rational number and a real number
How do i find the Perimeter of a [__] only having the A=25m2 and W=2.5 m
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-- You know the area of a rectangle, and you know its width.
Let's pause here, and gather up a few tools to do the job with. The tools you'll need are the things that you know about rectangles. Definitions of the area and perimeter of a rectangle would be very helpful.
=> Area of a rectangle = (length) x (width)
=> Perimeter of a rectangle = (length+width + length+width) = 2 (length+width)
You know all the numbers in both of these formulas, except the length. Can you think of a way to find it, using the numbers that you do know ?
Take the area formula . . . . . Area = (L) times (W)
Put in the numbers you know: 25 m² = (L) x (2.5 m)
Divide each side by 2.5 m : (25 m²) / (2.5 m) = L
10 m = L
Now you know both 'L' and 'W'. so ... Time to go directly to the perimeter formula:
Perimeter = 2 (L + W)
= 2 (10m + 2.5m)
= 2 (12.5 m)
= 25 m
Factor completely. n^2 + 7n - 44
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(n+11)(n-4) is your answer
Answer:
the answer is (n+11)(n-4)
Step-by-step explanation:
How do you determine whether three sets of points is collinear
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I think you mean "a set of three points". What I would do is take one point, find the slope from that point to another one, and then find the slope from the same starting point to the third one. If the (absolute values of the) slopes from the same starting point to each of the others are equal, then the three points are collinear.
Step 1)Write an equation of the line determined by two of the points.
Unless the y-intercept is too hard to find, we're probably going to use slope-intercept form to accomplish this. Slope-intercept form is written as where m is the slope and b is the y-intercept (the value of y when x = 0)
Step 1a) We find the slope with the change in the y-coordinates of the two points (the "rise") over the change in the x-coordinates. (the "run")
Step 1b) We can use this slope to find the y-intercept, the value of y when x = 0. We know how y changes accordinate to changes in x by the slope. Just take one of the points of our line, see how much x needs to change to become equal to 0, and change y accordingly.
Step 2) We can take our third point and plug in its x and y values in that equation, now that we have the equation of our line filled out. If you evaluate the equation and it is true, then the point is on that line. If it's not true for those values, the point is not on the line.