MATHEMATICS HIGH SCHOOL

Find the value or values of y in the quadratic equation y2 + 4y + 4 = 7

Answers

Answer 1
Answer: Hello,

y²+4y+4=7
==>(y+2)²-7=0
==>(y+2-√7)(y+2+√7)=0
==>y=-2+√7 or y=-2-√7
Answer 2
Answer:

Hey man this is how i did it. I think it's right. Not sure

y²+4y+4=7

Then (y+2)²-7=0

Separate (y+2-√7)(y+2+√7)=0

Simplify y=-2+√7 or y=-2-√7

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A dartboard has a diameter of 18 inches.What are its radius and circumference?

Answers

Diameter of the dartboard as given in the question = 18 inches
Then
Radius of the dartboard will be = 18/2 inches
                                                  = 9 inches
We already know that
Circumference of a circle = 2πr
We also know that the value of π = 3.14159
Then
Circumference of the dartboard = 2 * 3.14159 * 9 inches
                                                    = 56.548 inches
                                                    = 56.55 inches
So the radius of the dartboard is 9 inches and the circumference of the dartboard is 56.55 inches. I hope the procedure is absolutely clear to you.

Which of the following expresses the number ofmeters a contestant must travel in a 3-lap race where
the course is a circle of radius R meters?
F. 3R
G. 3πR
H. 3πR^2
J. 6R
K. 6πR

Answers

1\ lap\to2\pi R\n\n3\ lap\to3\cdot2\pi R=6\pi R\n\nAnswer:K.

Please help me... Brainiest to best answer

Answers

Answer:

it is eathier negitive 8 or positive 8

Step-by-step explanation:

hope this helpsss

Two of the angles of a triangle are 65° What is the measure of the third angle? O 65 O 130° O Cat they O 50​

Answers

Answer: The answer is 50°

Step-by-step explanation: 65 + 65=130    180-130=50

Image 1
____________________________________________
image 2

Answers

cosine of angle F = adjacent side / hypotenuse
Cosine of angle F = 60/61 Option C

In image 2, we have to find out the adjacent side
adjacent side =√ 41² - 40² = √81 = 9

Cosine of angle X = 9/41
Option C

Please help with sequences and series problem!

Answers

In an arithmetic sequence, consecutive terms are separated by a common difference d and are given recursively by

a_n=a_(n-1)+d

So we can write a_(51) in terms of a_(11) by substituting recursively:

a_(51)=a_(50)+d

a_(51)=(a_(49)+d)+d=a_(49)+2d

a_(51)=(a_(48)+d)+2d=a_(48)+3d

and so on up to

a_(51)=a_(11)+40d

(notice how in a_x+yd, it's always true that x and y add up to 51)

We're given that a_(11)=23 and a_(51)=183, so we can solve for d:

183=23+40d\implies40d=160\implies d=40

We can use the same strategy to find the first term in the sequence:

a_(11)=a_(10)+40

a_(11)=(a_9+40)+40=a_9+80

a_(11)=(a_8+40)+80=a_8+120

and so on up to

a_(11)=a_1+400

23=a_1+400\implies a_1=-377

In general, the sequence has a pattern of

a_n=a_(n-1)+40

a_n=(a_(n-2)+40)+40=a_(n-2)+2\cdot40

a_n=(a_(n-3)+40)+2\cdot40=a_(n-3)+3\cdot40

and so on up to

a_n=a_1+(n-1)\cdot40

So this sequence is given by the rule

a_n=-377+40(n-1)\implies \boxed{a_n=40n-417}
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