6. Minimum value determined by the formula function f (x) = 2x ²-8x + p was 20. Value f (2) is.7. Shape factor of the quadratic equation 4x ²-13x = -3 is ...
8. Quadratic function whose graph passes through the point (-12.0) and has a turning point (-15.3) is ..
9. Roots of a quadratic equation: 4x ² + px +25 = 0 are x1 and x2, if the roots of the quadratic equation x1 ² + x2 ² = 12.5 then the value of p is ....
10. Equation x ²-4x +3 = 0 and x ² +4 x-21 = 0, has a root persekutuan.Akar the alliance is

Answers

Answer 1

Answer: $6)\ \ \ f(x)=2x^2-8x+p\nthe\ minimum\ value =20\ \ \ \Leftrightarrow\ \ \ y_(\ of\ vertex)=20\ \ \ \Leftrightarrow\ \ \ - (\Delta)/(2a) =20\n\n\Delta=(-8)^2-4\cdot2\cdot p=64-8p\ \ \Leftrightarrow\ \ - (64-8p)/(2\cdot2) =20\ \ \Leftrightarrow\ \ -16+2p=20\n\n2p=36\ \ \ \Leftrightarrow\ \ \ p=18\ \ \ \Rightarrow\ \ \ \ f(x)=2x^2-8x+18\n\nf(2)=2\cdot2^2-8\cdot2+18=2\cdot4-16+18=8+2=10$

$7)\ the\ shape\ factor\ of\ the\ quadratic\ equation\ 4x^2-13x = -3\n is\ a=4\ \ \ (\ a>0\ \ \ \rightarrow\ \ \ the\ shape\ is\ \cup\ )\n\n8)\ \ \ the\ turning\ point=(-15;3)\ \ \ \Rightarrow\ \ \ f(x)=a(x+15)^2+3\n\n the\ graph\ passes\ through\ the\ point\ (-12.0) \ \Rightarrow\ \ 0=a(-12+15)^2+3\n\n\Rightarrow\ \ \ a\cdot3^2=-3\ \ \ \Rightarrow\ \ \ a=- (3)/(9) =- (1)/(3) \ \ \ \Rightarrow\ \ \ f(x)=- (1)/(3)(x+15)^2+3$

$\Rightarrow\ \ \ f(x)=- (1)/(3)(x^2+30x+225)+3=- (1)/(3)x^2-10x-72\n\n9)\ \ \ 4x^2+px+25=0\n\n\Delta=p^2-4\cdot4\cdot25=p^2-400\n\ntwo\ solutions\ \ \Leftrightarrow\ \ \Delta>0\ \ \Leftrightarrow\ \ p^2-40>0\ \ \Leftrightarrow\ \ (p-20)(p+20)>0\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \Leftrightarrow\ \ \ p\in(-\infty;\ -20)\ \cap\ (20;\ +\infty)\n-------------------------------$

$the\ Vieta's\ formulas\ to\ the\ quadratic\ equation\ ax^2+bx+c=0\n\nx_1+x_2=- (b)/(a) \ \ \ and\ \ \ x_1\cdot x_2= (c)/(a) \n------------------------------\n\nx_1+x_2=- (p)/(4) \ \ \ and\ \ \ x_1\cdot x_2= (25)/(4) \n\nx_1^2+x_2^2=x_1^2+2\cdot x_1\cdot x_2 +x_2^2-2\cdot x_1\cdot x_2 =(x_1+x_2)^2-2\cdot x_1\cdot x_2 \n\nx_1^2+x_2^2=(x_1+x_2)^2-2\cdot x_1\cdot x_2 \ \ \ \Leftrightarrow\ \ \ 12.5=(- (p)/(4) )^2-2\cdot (25)/(4) \n\n$

$12.5= (p^2)/(16) +12.5 \ \ \ \Leftrightarrow\ \ \ (p^2)/(16)=0 \ \ \ \Leftrightarrow\ \ \ p^2=0 \ \ \ \Leftrightarrow\ \ \ p=0\n\n\n10)\ \ \ x^2-4x+3=0\ \ \ and\ \ \ x^2+4x-21=0\n\n x^2-4x+3=x^2+4x-21\ \ \Leftrightarrow\ \ -4x-4x=-21-3\n\n\ \ \Leftrightarrow\ \ -8x=-24\ \ \Leftrightarrow\ \ x=3$

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Is WXY ~ ZYV? Justify your answer. The image is not drawn to scale.A. No, the sides are not in proportion.
B. No, the corresponding angles are not congruent.
C. Yes, WXY ~ ZYV with a scale factor of 9:8.
D. Yes, WXY ~ ZYV with a scale factor of 8:9.

Answers

Answer: C. Yes, WXY ~ ZYV with a scale factor of 9:8.

Step-by-step explanation:

In the given picture, we have two triangles Δ WXY and Δ ZYV in which

$\angle {X}=\angle{Y}$ [Right angle]

$\angle {W}=\angle{Z}$

Therefore, by AA- similarity postulate, we have

$\triangle{WXY}\sim\triangle{ZYV}$

The scale factor is given by :-

$k=(WX)/(ZY)=(XY)/(YV)=\frac{WY]{ZV}$

$\Rightarrow k=(18)/(16)=(6.75)/(6)=(22.5)/(20)=(9)/(8)$

Hence, $\triangle{WXY}\sim\triangle{ZYV}$ with scale factor of 9:8 .

I hope this helps you

Which sentence uses punctuation correctly?a. Beneath the tall, tree the family ate a picnic of fruit and muffins.
b. Beneath the tall tree the family ate, a picnic of fruit and muffins.
c. Beneath the tall tree, the family ate a picnic of fruit and muffins.
d. Beneath the tall tree the family ate a picnic of fruit and muffins.

Answers

C. Beneath the tall tree, the family ate a picnic of fruit and muffins.

PLEASE HELPA hot air balloon is at a height of h feet.
Which expressions represent a change in height of 5 ft?
Choose exactly two answers that are correct.
A. h/5
B. 5*h
C. h+5
D. h-5
I have more questions do if you are willing to help with more than this than let me know.

Answers

Since the balloon is at h height and has a change of 5 ft that means it could go up (+5) or down (-5) ft. So the answer would be c and D

h+5 and h-5

3 1/3 - 2 2/5 what is the answer?

Answers

One way to solve this is by changing the mixed numbers to improper functions.
3 1/3 = 10/3
2 2/5 = 12/5

The next step I would take is to find a common denominator.
10/3 = 50/15
12/5 = 36/15

Now we can solve the original equation:
50/15 - 36/15 = 14/15

Since 14/15 is already simplified this is your final answer.

What are the domain, range, and asymptote of h(x) = 6x – 4?

Answers

The domain is x = 1, 2, 3, 4, 5...... ∈ R (set of real number).

Range: (0,∞)

Asymptote: y=0.

What is Domain, Range and Asymptote?

The range of a function is the set of output values for the dependent variable.

The range, however, is bounded by the horizontal asymptote of the graph of f(x).

A straightline that continuously approaches a certain curve without ever meeting it is an asymptote.

Given:

h(x) = 6x – 4

Now, the domain is the input value as

x = 1, 2, 3, 4, 5...... ∈ R (set of real number)

So, h(1) = 6-4 =2

and, h(2) = 12-4 = 8

and, the range is (0,∞)

Now, the asymptote h(x)= 0

6x-4 = 0

x= 2/3.

Learn more about Domain and Range here:

brainly.com/question/28135761

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h(x)=6x−4 or h(x)=6x−4
If the former, the domain is all real numbers, often denoted by the symbol R.
the range is (0,∞)
asymptote is y = 0

What is the solution to the equation 1.6m − 4.8 = −1.6m?m = 0.5

m = 0.7

m = 1.5

m = 3

Answers

m = 1.5 is the solution to the equation.

What is the equation ?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign. For example, 3x – 5 = 16 is an equation. Solving this equation, we get the value of the variable x as x = 7.

1.6m-4.8=-1.6m

Subtract 1.6m to both sides to get

-4.8=-3.2m

Divide both sides by -3.2to get

x = 1.5

m = 1.5 is the solution to the equation.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.

To learn more about An equation, refer

brainly.com/question/14107099

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see attached picture for answre

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