Partial products and regrouping are similar in breaking down complex calculations but differ in their application, partial products for multiplication and regrouping for addition/subtraction and methods partial products involve multiplying digits while regrouping involves carrying or borrowing digits.
Given that,
Compare partial products and regrouping.
Now, Partial products is a multiplication method where you break down a larger multiplication problem into smaller, more manageable parts.
Multiply each digit of one number by each digit of the other number and then add up all the partial products to get the final answer.
For example, if you were to multiply 23 by 45 using partial products, you would multiply 2 by 4, then 2 by 5, then 3 by 4, and finally 3 by 5.
Then, add up all these partial products to get the final result.
Now, Regrouping is a method used in addition and subtraction when the sum or difference of two digits is greater than 9.
In regrouping, carry the extra value to the next place value or borrow from the next place value to ensure an accurate calculation.
For example, if you were to add 78 and 65, you would regroup when adding the units digit (8 + 5 = 13).
Then, carry the 1 to the tens place and add it to the sum of the tens digits (7 + 6 + 1 = 14).
Now, compare the two methods:
Alike: Both partial products and regrouping involve breaking down larger problems into smaller, more manageable parts.
They both help in simplifying complex calculations and finding accurate results.
Different: Partial products are specifically used for multiplication while regrouping is mainly used in addition and subtraction.
Partial products involve multiplying each digit to get partial results, while regrouping involves carrying or borrowing digits to ensure accuracy in calculations.
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The feedback the other lab group should give is (d) the line of best fit is not reasonable because it has more points below it than above it.
From the scattered plot (see attachment), we can see that the scattered plot has a total of 7 dots,
There are more points below the scattered plot, than above it.
This means that the scattered plot is not reasonable because of (d)
Read more about scattered plots at:
Answer:
The correct option is;
The line of best fit is not reasonable because it has more points below it than above it.
Step-by-step explanation:
Here we note that there are a total of seven points in the scatter plot and there are five of the points below the line of best fit and just two above the line.
Of the five points below the line of best fit, four are just about touching the underside of the line while one of the two points above the line is just about touching the line.
The proper positioning of the line can be reviewed, therefore, with a line drawn through the four points presently touching the underside of the line of best fit.
Select one:
a. Vertex: (0, 6)
Axis of symmetry: x = 0
b. Vertex: (6,0)
Axis of symmetry: x = 6
c. Vertex: (0, -6)Axis of symmetry: x = 0
d. Vertex: (-6, 0)
Axis of symmetry: x = -6
Answer:
C.
forgetting to include miscellaneous income earned
Step-by-step explanation:
Regular pay: $12/hour
Time and a half: $12/hour * 1.5 = $18/hour
40 hours * $12/hour + 2 hours * $18/hour = $480 + $36 = $516
Answer: $516
The total value of the 12 bills is $115.
How many $5 bills and how many $10 bills does he have?
Answer-
The line equation is,
Solution-
The line meets x-axis at the point M, i.e M is the x-intercept of this line. At the x-intercept y=0, so
So, coordinate of M is
The line meets y-axis at point N, i.e N is the y-intercept of this line. At the y-intercept x=0, so
So, coordinate of N is
The line joining M and N can be found out by applying two point formula of straight line,
As it is given that all the coefficients are integers, so multiplying with 3
Solution: As given line y =3x-5 meet x-axis at the point M.
On x axis y coordinate is zero.
Put y =0 in above equation, we get →x = 5/3
∴ Coordinate of M is (5/3,0).
As, also given , line 3y+2x=2 meets y-axis at point N.
On y axis , x coordinate is zero.
Substituting , x=0 in above equation, gives y =2/3.
Coordinate of point N is (0,2/3).
Equation of line passing through two points (a,b) and (p,q) is given by
→
Or as X intercept = 5/3, and Y intercept = 2/3
Equation of line in intercept form is →, where a and b is X intercept and y intercept respectively.
So, line passing through (5/3,0) and (0,2/3) is given by
→
→
→ 6 x + 15 y =10 [Taking LCM of 5 and 2 which is 10]
→ 6 x + 15 y -10=0, which is equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.