MATHEMATICS HIGH SCHOOL

Peyton has nn nickels and dd dimes. She has no less than 21 coins altogether. Write this situation as an inequality.

Answers

Answer 1
Answer:

Answer:

N+D _>21

Step-by-step explanation:

N= The number of nickel

D= The number of dimes

So it is n+d less than with the line under it 21
Answer 2
Answer:

Answer:

n+d _>18

Step-by-step explanation:

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Find the least common denominator (LCD) of
7/12 and 3/2

Answers

Answer:

12

Step-by-step explanation:

Rewriting input as fractions if necessary:

7/12, 3/2

For the denominators (12, 2) the least common multiple (LCM) is 12.

LCM(12, 2)

Therefore, the least common denominator (LCD) is 12.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

7/12 = 7/12 × 1/1 = 7/12

3/2 = 3/2 × 6/6 = 18/12

Find the point-slope form of the line that passes through given the point and has the given slope.Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution. (0, 0)
m = 2

- I have several questions like this that I have no clue how to solve. This is all the information provided by my lesson.

Answers

y - y1 = m(x - x1)
slope(m) = 2
(0,0)...x1 = 0 and y1 = 0
now its just a mater of subbing
y - 0 = 2(x - 0) <===

Of 81 square feet and a base length of 9 feet. What is the height of the parallelogram?

Answers

Your answer would be 9 feet
81=area
9=base
_=height
and area is base x hight so you divide the base by the area so an equation would be 81=9x then you would flip it around so it would be 9÷81=x
x=9
Hope this helps!!

I NEED HELP FAST. DUE TOMORROW

Answers

so it asks you to use the quadratic formula which is when you have ax^2+bx+c=0 then you put it into the quadratic formula which is x=((-b+-√(b^2-4ac))/(2a))

so 8x^2+3x=-7
add 7 to both sides
8x^2+3x+7=0

put into the quadratic formula
8x^2+3x+7=0
ax^2+bx+c=0
x=((-b+-√(b^2-4ac))/(2a))
x=((-3+-√(3^2-4(8)(7)))/(2(8)))
 solve inside of square root first
3^2-4(8)(7)=pemdas 9-4(8)(7)=9-224=-215

so -3+-√-215
we know that square root of negative is not real and is immaginary so i must be involved
√-1=i so
-215=i√215
so the answer is A






CONTINUATION
i√215=i(15)=15i
-3+-15i means -3+ or minus 15i
then solve for botom part
2(8)=16
(-3+-15i)/16
so the answers are (-3+15i)/16 and (-3-15i)/16

Show me how to solve the following problem 12.4 divided by two- fifths

Answers

12.4 divided by 2/5
Start by converting the decimal into fraction;
12.4÷0.4
= 31
Write it down as (124/10)/(2/5). So when you divide fractions you can flip it as (124/10)*(5/2). So after that cross cancel and you can get 31

If t is any real number, prove that 1+(tant)^2=(sect)^2

Answers

1+\left(tant\right)^2=\left(sect\right)^2\n\nL=1+\left((sint)/(cost)\right)^2=1+(sin^2t)/(cos^2t)=(cos^2t)/(cos^2t)+(sin^2t)/(cos^2t)=(cos^2t+sin^2)/(cos^2t)=(1)/(cos^2t)\n\n=\left((1)/(cost)\right)^2=(sect)^2=R\n\n====================================\n\n\ntanx=(sinx)/(cosx)\n\nsin^2x+cos^2x=1\n\nsecx=(1)/(cosx)
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