What is the equation in point-slope form for the line parallel to y = –2x + 10 that contains J(6, 8)?Choose one answer.
a. x – 8 = 2(y – 6)
b. y – 8 = 2(x – 6)
c. y + 8 = –2(x – 6)
d. y – 8 = –2(x – 6)

Answers

Answer 1

Answer: y-y1= m(x1-x2)
using this formula
the answer is d
because slope has to remain the same if its parallel

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I don't care for an explanation PLEASE JUST HELP!!! It would mean a lot !!!! Thanks
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HELP ME PLEASEMatch each transformation or sequence of transformations to an equivalent transformation or sequence of transformations.
a 90° counterclockwise rotation about the origin
a 180° rotation about the origin
a 90° clockwise rotation about the origin
a 90° counterclockwise rotation about
the origin and then a 180° rotation
about the origin

arrowRight
a reflection across the x-axis and then a
reflection across the y-axis
arrowRight
a 90° clockwise rotation about the origin
and then a rotation 180° about the origin
arrowRight

Answers

Answer:

a 90° counterclockwise rotation about the origin

a 180° rotation about the origin

a 90° clockwise rotation about the origin

a 90° counterclockwise rotation about

the origin and then a 180° rotation

about the origin

Step-by-step explanation:a 90° counterclockwise rotation about the origin

a 180° rotation about the origin

a 90° clockwise rotation about the origin

a 90° counterclockwise rotation about

the origin and then a 180° rotation

about the origin

Final answer:

A 90° counterclockwise rotation is the same as a 270° clockwise rotation. A 180° rotation is the same as a reflection across both axes. A 90° clockwise rotation is the same as a 270° counter-clockwise rotation. Two separate rotations of 90° counter-clockwise and then 180° are the same as rotations of 90° clockwise and then 180°.

Explanation:

In mathematics, especially in geometry, transformations involve changing the position, size or shape of a figure. The question is about matching specific transformations or sequence of transformations to its equivalent transformation.

A 90° counterclockwise rotation about the origin is equivalent to a 270° clockwise rotation about the origin because they both result in the same final position.
A 180° rotation about the origin is equivalent to a reflection across the x-axis and then a reflection across the y-axis. Both of these transformations result in the figure being flipped over the origin.
A 90° clockwise rotation about the origin is equivalent to a 270° counterclockwise rotation about the origin as they both result in the same final position.
A 90° counterclockwise rotation about the origin and then a 180° rotation about the origin is equivalent to a 90° clockwise rotation about the origin and then a rotation 180° about the origin because they both result in the same final position.

Learn more about Geometry Transformations here:

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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimeter of the window is 12 feet. what dimensions will produce a window of maximum area? (Round you answers to two decimal places ) what is the width x= what is the length y.?(Question2) write the function in the form f(×) = ×^3- 6×^2- 15×+9, k = -2.
f (×)=?

Answers

Let's find the perimeter of the window.

The bottom side is $x$ . The left and right sides make $2y$ .
The perimeter of a circle is $2\pi r$ , so the perimeter of a semicircle must be $\pi r$ , The radius is $\frac{1}2x$ , so that gives $\frac{1}2\pi x$ for the curve. All of that is equal to 12.

$x+2y+\frac{1}2\pi x=12$

We only want to use one variable to create the area formula, so let's solve for $y$ .

$2y=12-x-\frac{1}2\pi x$

$y=6-\frac{1}2x-\frac{1}4\pi x$

Now that we have a value for $y$ in terms of $x$ , we can find the area in terms of $x$ .

The area of the rectangle is going to be $xy$ , which then becomes

$A_r=x(6-\frac{1}2x-\frac{1}4\pi x$

$A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2$

The area of the semicircle is going to be $\frac{1}2\pi r^2$ .

Since $r=\frac{1}2x$ , $A_(sc)=\frac{1}2\pi (\frac{1}2x)^2$ .

$A_(sc)=\frac{1}2\pi \frac{1}4x^2$

$A_(sc)=\frac{1}8\pi x^2$

Now let's add the areas of the rectangle and semicircle.

$A=A_r+A_(sc)$

$A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2$

$A=6x-\frac{1}2x^2-\frac{1}8\pi x^2$

If you wanted to factor out $\frac{1}8$ like you did, this would become

$\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}$

Now what we want to do is find what $x$ is when $A$ is at its highest point, Once we have the value for $x$ we can also find the value for $y$ , of course.

Let's put our equation in the general form of a quadratic.

$A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x$

Now we can use the vertex formula $x=(-b)/(2a)$ .
( $a$ and $b$ refer to $ax^2+bx+c$ .)

$x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}$

$x=\frac{-6}{-\frac{1}4\pi -1}$

$x=(-24)/(-\pi -4)$

$\boxed{x=(24)/(\pi +4)}$

Now let's plug that in for $y=6-\frac{1}2x-\frac{1}4\pi x$ .

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use $x\approx3.36059492$ .

$y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)$

$y\approx6-(1.68029746+2.63940507809)$

$\boxed{y\approx1.68029746191}$

Let's take our answers for $x$ and $y$ and round to 2 decimal places.

$\boxed{x\approx 3.36\ ft}$

$\boxed{y\approx 1.68\ ft}$

The inner and outer Radii of a cylindrical pipe are 5 cm and 4 cm respectively. find the area of cross section of the pipe.

Answers

To do this find the area of the inner pipe, and then find the area of the outer pipe, then subtract the larger of the two from the smaller, and that is the area of the cross section

Answer:

28.3 cm²

Step-by-step explanation:

You find the area of the whole section which is 5²π = 25π.

Then you find the area of the empty part which is 4²π = 16π.

Then you subtract to get 9π which is 28.27433388......

= 28.3 cm²

Find the slope of the line that passes through the points (3, 2) and (-2, -2). 5/4 4/5 -4

Answers

Answer:

m = 4/5

Step-by-step explanation:

m = slope

$m=(y_2-y_1)/(x_2-x_1)$

$m=(-2-2)/(-2-3)$

$m=(-4)/(-5)$

$m=(4)/(5)$

Solve the equation 3-x/5-4-x/2=1

Answers

Hi Ponie

Simplify both sides of the equation

3-x/5-4-x/2=1

3+ -1/5 x+ -4+ -1/2 x =1

Combine like terms

(-1/5 x + -1/2 x)+(3+-4)=1

-7/10 x +-1=1

-7/10 x -1=1

Add 1 to both sides

-7/10 x-1+1=1+1

-7/10 x=2

Multiply both sides by 10/-7

(10/-7)*(-7/10 x )= (10/-7)*2

x= -20/7

I hope that's help and I am sorry for the late answer !

The gradient of the graph shown and given in its simplest form

Answers

Answer:

1/2

Step-by-step explanation:

Gradient=∆x/∆y

m=(0--1.5)÷(0-3)

m=1/2

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What is the equation in point-slope form for the line parallel to y = –2x + 10 that contains J(6, 8)?Choose one answer.a. x – 8 = 2(y – 6) b. y – 8 = 2(x – 6) c. y + 8 = –2(x – 6) d. y – 8 = –2(x – 6)

Answers

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Final answer:

Explanation:

Learn more about Geometry Transformations here:

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What is the equation in point-slope form for the line parallel to y = –2x + 10 that contains J(6, 8)?Choose one answer.
a. x – 8 = 2(y – 6)
b. y – 8 = 2(x – 6)
c. y + 8 = –2(x – 6)
d. y – 8 = –2(x – 6)