Nadine can send or receive a text message for 15 cents or get an unlimited number for 5 dollars. Write and solve an inequality to find how many messages she can send and receive so the unlimited plan is cheaper than paying for each message.

Answers

Answer 1
Answer:

After solving the equation according to the given statement it is clear that if she sends or receives more than 33 text messages then she has to pay more than $5.

What is inequality?

Inequality is a declaration of the relation of larger, greater or equal to, smaller, and less than or equal to between two digits or mathematical expressions. Either queries or theorems can be used to express inequality problems, and both can be solved using similar methods to those used to solve the equation.

As per the information obtained from the question,

$0.15x>$5.00

x>33.3333

So if she sends or receives more than 33 text messages, she will be paying more than $5.00.

To know more information about inequality:

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Answer 2
Answer: $0.15x>$5.00
x>33.3333
So if she sends or receives more than 33 text messages, she will be paying more than $5.00.

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10. angle GHI is an isosceles triangle with GI HI. IF GH is three more than x, HI is 17 less than fourtimes x, and GI is 45 less than six times x, find x and the measure of each side.

Three single-digit numbers multiply to make 504          Write the missing numbers

Answers

Find for the 3 single digit number that will be multiplied together to get the product 504.
=> n x n x n = 504 – where n are the single digits that we need to multiply.
504 / 2 = 252
504 / 3 = 168
504 / 4 = 126
504 / 5 = 100.8
504 / 6 = 84
504 / 7 = 72
504 / 8 =63
504 / 9 = 56
Now, let’s have 7 8 9 as 3 numbers to multiply to get 504 as product.
=> 7 x 8 x 9
=> 504





The correct answers are:

7, 8 and 9.

Explanation:

We can check divisibility using the rules of divisibility. We will start with the largest single-digit number, 9. The rule for divisibility by 9 is that the sum of the digits is divisible by 9. The digits of 504 add to 5+0+4=9; since 9 is divisible by itself, 504 is divisible by 9.

504/9 = 56; this means we need two single digit numbers that are factors of 56. 56 = 7*8; this means 7 and 8 are our other two numbers.

A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find the length of the rectangle

Answers

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

The area of rectangle is given as:

\text {Area of rectangle }=\text { length } * \text { width }

Substituting the values we get,

\begin{array}{l}{3197=(7 W-22)(W)} \n\n {3197=7 W^(2)-22 W} \n\n {7 W^(2)-22 W-3197=0}\end{array}

On solving the above quadratic equation using quadratic formula,

\text {For the quadratic equation } a x^(2)+b x+c=0 \text { where } a \neq 0

x=\frac{-b \pm \sqrt{\left(b^(2)-4 a c\right)}}{2 a}

\begin{array}{l}{\text {Here in } 7 \mathrm{W}^(2)-22 \mathrm{W}-3197=0} \n\n {a=7 ; b=-22 ; c=-3197}\end{array}

Substituting in above quadratic formula,

\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^(2)-4(7)(-3197)\right)}}{2 * 7}} \n\n {W=(22 \pm √(90000))/(14)=(22 \pm 300)/(14)} \n\n {W=(22+300)/(14) \text { or } W=(22-300)/(14)} \n\n {W=23 \text { or } W=-19.85}\end{array}

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

Is 6.700 equal to 6.7?

Answers

Yes because zeros have no value if they are after a decimal and have no number behind them
the answer is yes because they are the same number.

Polygon ABCD is plotted on a coordinate plane.If the polygon translates 3 units to the left and 1 unit down,the length of diagonal A’C’ is __ units ( 2,3or 6) if the polygon translates 3 units further to the left and four units down, the length of diagonal A’C’ ( increases,decreases or remains the same

Answers

  Length of diagonal A'C' will be 2 units and it will remain the same even after multiple translations.      

   Length of a segment joining two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Length between two points = √((x_2-x_1)^2+(y_2-y_1)^2)

Therefore, length of diagonal AC joining points A(3, 4) and C(3, 2) will be,

AC = √((3-3)^2+(4-2)^2)

     = 2 units

If the polygon ABCD is shifted left, right, up and down, translations done will be the rigid transformations showing no change in shape and size of the polygon.

    Therefore, length of diagonal A'C' will be 2 units and it will remain the same when the polygon is translated.

Learn more,

brainly.com/question/1761538

The length of the diagonal will be 2.

When a translation is performed on a shaped, it simply moves location. The size and shape of the object do not change. Therefore, the length of AC will remain the same at all times.

HELP PLEASE!!!!!! I need help on 5. My answer was wrong. THIS IS DUE TOMORROW. 25 points for this.

Answers

Answer:

57

Step-by-step explanation:

Because side BD is similar to side BA

triangle BCD seems to be double the size of triangle BAD

By finding the side lengths of the missing sides BC and CD you can get the perimeter.

Because we know the triangle is double the size you can double the lengths of AD and BD to get 24 and 18, if you add 6,9,24, and 18. You will get 57.

HELPFor the system below solve using linear combinations method 4x-7y=-2 and 12x-21y=-42

Answers

No solution 

cz 

12x-21y=-42   -----> /3  (divided by 3 )
4x-7y=14  ------ (2)
4x-7y=-2  ------- (1)

how 4x-7y =14 an = -2

and if we 
(2)-(1)
0=12  
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