Answer:between 2 and 3, not including. Interval notation: (2,3)
Step-by-step explanation:
Factor: x^2 -5x + 6 —> (x-3)(x-2)<0
Change sign to = and solve: x = 2 , 3
these are the x intercepts, the equation is not reflected over the y axis so we know the rest of the arc of the parabola is between 2 and 3
Answer:
The arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f g)(x) = ,
Solution:
Given, two functions are f(x) = x + 2 and g(x) = x – 2
We need to find the arithmetic combinations of given two functions.
Arithmetic functions of f(x) and g(x) are (f + g)(x), (f – g)(x), (f g)(x),
Now, (f + g)(x) = f(x) + g(x)
= x + 2 +x – 2
= 2x
Therefore (f + g)(x) = 2x
similarly,
(f - g)(x) = f(x) - g(x)
= x + 2 –(x – 2)
= x + 2 –x + 2
= 4
Therefore (f - g)(x) = 4
similarly,
(f g)(x) = f(x) g(x)
= (x + 2) (x – 2)
= x (x – 2) + 2 (x -2)
Therefore (f g)(x) =
now,
=
Hence arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f g)(x) = ,