PHYSICS HIGH SCHOOL

The cloud of interstellar dust and gas that forms a star is known as a A. protostar.
B. white dwarf.
C. red giant.
D. nebula.
User:
15. With an average surface temperature of about 737 K, _______ is the hottest planet.
A. Mars
B. Mercury
C. Earth
D. Venus

Answers

Answer 1
Answer:

Correct answer choice for question 1 is:


D) Nebula.


Explanation:


A nebula is an interstellar cloud of dust, hydrogen, helium and other ionized vapors. Basically, the nebula was a sign for any distributed enormous object, including galaxies behind the Milky Way. Most nebulae are of a large size, some are numbers of light years in diameter. A nebula that is almost visible to the human eye from Earth would appear larger, but no flashing, from close by. The Orion Nebula, the glowing nebula in the sky that controls a region twice the diameter of the full Moon, can be observed with the naked eye but was dropped by early scientists.

Correct answer choice for question 2 is :


D) Venus


Explanation:


Venus is the second planet from the Sun, revolving it every 224.7 Earth days. It has the largest revolution time of any planet in the Solar System and turns in the different direction to most other planets. It does not have any real satellites. It is the second glowing natural object in the night sky after the Moon, leading an obvious magnitude of 4.6 bright quite to throw shadows at night and, unusually, obvious to the naked eye in full daylight.
Answer 2
Answer:      The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.

Related Questions

Suppose you decide to cut the wire into two pieces (not necessarily the same length) to shape into two circles. Write a function A ( x ) which models the total area of the two circles in terms of x , the length of one of the pieces of wire. (It may be helpful to use for a circle A = πr 2 and C = 2 πr ). Then find the length x that will minimize the total area.
Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.60 × 10-19 C. Find the charge on an oil drop weighing 1.00 × 10-14 N and suspended in a downward field of magnitude 2.08 × 104 N/C.
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1. -------- of an object is the change in velocity per unit time.a) Displacement b) Acceleration c) Average velocity d) Angular velocity.2. The motion of freely falling body is an example of ----- motion.a) Uniform motion b) Non -uniform motion c) Uniformly accelerated motion. d) None of these.
an ampere is the si unit of which of the following? electric power, electric current, resistance, electric potential difference

What is difference between kilowatt and kilowatt hour?

Answers

Those two units can be compared to a 'mile per hour' and a 'mile per hour - hour'.
One is a rate.  The other is a quantity, after maintaining a rate for some time.

-- 'Joule' is a unit of energy.  It's the amount of work (energy) you do
when you push with a force of 1 newton though a distance of 1 meter.
Lifting 10 pound of beans 3 feet off the floor takes about 40.7 joules of energy.

-- 'Watt' is a rate of using energy . . . 1 joule per second.
If you lift 10 pounds 3 feet off the floor in 1 second, your power is 40.7 watts.

-- 'Watt-second' is the amount of energy used in one second,
at the rate of 1 joule per second . . . 1 joule.

-- 'Watt-hour' is the amount of energy used in one hour,
at the rate of 1 joule per second . . . 3,600 joules.

-- 'Kilowatt' is a bigger rate of using energy . . . 1,000 joules per second.

-- 'Kilowatt - second' is the amount of energy used in one second,
at the rate of 1,000 joules per second . . . 1,000 joules .

-- 'Kilowatt - hour' is the amount of energy used in one hour,
at the rate of 1,000 joules per second . . . 3,600,000 joules .

Depending on where you live, 3,600,000 joules of energy bought
from the electric company costs something between 5¢ and 25¢.
Kilowatt hour is a measure of ENERGY
Kilowatt is a measure of POWER

A ray of monochromatic light (f=5.09x10^14 hz) passes through air and a rectangular transparent block calculate the absolute index of refraction for the medium of the transparent block Angle of incidence of the light ray as it enters the transparent block from air =40 degrees
The angle of refraction of the light ray as it enters the transparent block from air = 20 degrees
Calculate the absolute index of refraction from the medium of the transparent block

Answers

The right answer for the question that is being asked and shown above is that: "The angle of refraction of the light ray as it enters the transparent block from air = 20 degrees." A ray of monochromatic light (f=5.09x10^14 hz) passes through air and a rectangular transparent block calculate the absolute index of refraction for the medium of the transparent block 

Which best compares a brush and a commutator in an electric motor?

Answers

The purpose of the brush is supposed to be to lessen the amount of damage or wear placed upon the motor. I hope this helps with your answer choices since you did not post any.

Many physical quantities are connected by inverse square laws, that is, by power functions of the form f(x)=kx^(-2). In particular, the illumination of an object by a light source is inversely proportional to the square of the distance from the source. Suppose that after dark you are in a room with just one lamp and you are trying to read a book. The light is too dim and so you move halfway to the lamp. How much brighter is the light?

Answers

Answer:

  • 4 times

Explanation:

Since the equation for the illumination of an object, i.e. the brightness of the light, is inversely proportional to the square of the distance from the light source, the form of the function is:

  • f(x) = k.x⁻²

Where x is the distance between the object and the light force, k is the constant of proportionality, and f(x) is the brightness.

Then, if you move halfway to the lamp the new distance is x/2 and the new brightness (call if F) is :

F=k(x/2)^(-2)=(k)/((x/2)^2)= (k)/(x^2). 4=f(x).4

Then, you have found that the light is 4 times as bright as it originally was.

A car with a mass of 1800 kilograms is traveling at a speed of 29 m/s on a horizontal flat road. Calculate the radius of its path. Which formula must be used to solve this?

Answers

Answer:

Explanation:

r = v^2 / g

where:

r is the radius of the path (in meters)

v is the speed of the car (in meters per second)

g is the acceleration due to gravity (in meters per second squared)

In this case, v = 29 m/s and g = 9.81 m/s^2. Therefore, the radius of the car's path is:

r = 29^2 / 9.81 = 82.5 meters

So the answer is 82.5

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Answers


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