Let the event J = correct problems solved by Jacqueline,
and the event M = correct problems solved by Marc.
A. P(J) × P(M) = P(J ∩ M)
B. The probability that Jacqueline and Marc both can solve a problem in a math test is 0.93.
C. P(J) × P(M) = P(J ∪ M)
D. J and M are independent events.
E. The probability that Jacqueline and Marc both can solve a problem in a math test is 0.52
Answer:
Option A , D and E holds.
Step-by-step explanation:
Let the event J = correct problems solved by Jacqueline,
and the event M = correct problems solved by Marc.
Jacqueline solved 80% of problems correctly in a math
So, probability of correct problems solved by Jacqueline P(J)=0.80
Marc solved only 65% of the problems correctly.
So, probability of correct problems solved by Marc P(M)=0.65
Probability of correct problems Solved by Marc and Jacqueline :
=
=
=
So, Option E is correct.
we also know that and means intersection .
So, P(J) × P(M) = P(J ∩ M)
So, Option A is also correct.
Since option A holds .
So, property of independent events is satisfied :
Thus Option D also holds.J and M are independent events.
Hence Option A , D and E holds.
Answer:
20 Units
Step-by-step explanation:
RS plus ST equals RT.
Take this visual:
_____/_______________
R S T
5 un 15 un
Using the segment addition postulate, we can tell RS+ST=RT
5+15=20
Hope this helps :-)