Write an equation to represent eachrelationship. SOLVE THE EQUATION.
5 more than six times a number is the
same as that number decreased by ten.

Answers

Answer 1
Answer: n6+5=n-10
n6=n-15
n5=-15
n=-3
hope this helps:)

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Solve for x 2x^2+5x-1=0

1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,(k+b)/2)2. Point T is the midpoint of JH . The coordinate of T is (0, 4) and the coordinate of J is (0, 2). The coordinate of H is: a.(0, 6)
b.(0, 3)
c.(0, 7)
d.(0, 11)
3. What about this one Point (-4, 3) lies in Quadrant
a.I
b.II
c.III
d.IV 4. Point (6, 0) lies on the.
a.x-axis
b.y-axis
c.line y = x 5. Any line with no slope is parallel to the
a.x-axis
b.y-axis
c.line y = x 7. If the point (a,3) lies on the graph of the equation 5x + y = 8, then a=
a.1
b.-1
c.-7 8. If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its center point is
a.(5, 7)
b.(-5, 7)
c.(5, -7) 9. If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is
a.6
b.16
c.36 10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True or False.

Answers

1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)

2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)

3. Point (-4, 3) lies in Quadrant II

4. Point (6, 0) lies on the x-axis

5. Any line with no slope is parallel to the y-axis

7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1

8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)

9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6

10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True

Answer:  The answers are given below.

Step-by-step explanation:  The calculations are as follows:

(1). The mid-point of a line segment divides it in the ratio m : n = 1 : 1.

So, the co-ordinates of the mid-point of the segment joining the points (a, b) and (j, k) are

\left((mj+na)/(m+n),(mk+nb)/(m+n)\right)\n\n\n=\left((* j+1* a)/(1+1),(1* k+1* b)/(1+1)\right)\n\n\n=\left((j+a)/(2),(k+b)/(2)\right).

So, the co-ordinates of the mid-point are\left((j+a)/(2),(k+b)/(2)\right).

Thus, (d) is the correct option.

(2). The co-ordinates of the points 'T' and 'J' are (0, 4) and (0, 2) respectively.

Let, (a, b) be the co-ordinates of the point 'H'.

Since 'T' is the mid-point of the line segment JH, so we have

(0,4)=\left((0+a)/(2),(2+b)/(2)\right)\n\n\n\Rightarrow (0,4)=\left((a)/(2),(2+b)/(2)\right)\n\n\n\Rightarrow (a)/(2)=0,~~~(2+b)/(2)=4\n\n\n\Rightarrow a=0,~~\Rightarrow 2+b=8~~~\Rightarrow b=6.

So, the co-ordinates of 'H' are (0, 6).

Thus, (a) is the correct option.

(3). The given point is (-4, 3).

Since 'x' co-ordinate is negative and 'y' co-ordinate is positive, so the given point lies in Quadrant II.

Thus, (b) is the correct option.

(4). The given point is (6, 0).

Here, 'y' co-ordinate is zero, so the point lies on the X-axis.

Thus, (a) is the correct option.

(5). The slope-intercept form of a line is

y = mx + c, where, 'm' is the slope and 'c' is the y-intercept.

If slope, m = 0, then the equation becomes

y = 0 × m + c

⇒ y = c, which is the equation of a line parallel to X-axis.

Thus, option (a) is correct.

(7). The point (a, 3) lies on the graph of the equation 5x + y = 8, so we have

5x+y=8\n\n\Rightarrow 5* a+3=8\n\n\Rightarrow 5a=5\n\n\Rightarrow a=1.

Thus, (a) is the correct option.

(8). Given that the equation of a circle is

(x+5)^2+(y-7)^2=36~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that the equation of a circle with centre (g, h) and radius 'r' units is given by

(x-g)^2+(y-h)^2=r^2.

Comparing equation (i) with the above general equation, we get

(g, h) = (-5, 7).

So, the centre point is (-5, 7).

Thus, option (b) is correct.

(9).  Given that the equation of a circle is

(x+5)^2+(y-7)^2=36~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

We know that the equation of a circle with centre (g, h) and radius 'r' units is given by

(x-g)^2+(y-h)^2=r^2.

Comparing equation (ii) with the general equation, we get

r² = 36   ⇒ r = 6 units.

So, the radius is 6 units.

Thus, option (a) is correct.

(10). Given that the equation of a circle is

(x-2)^2+(y-6)^2=4~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

We know that the equation of a circle with centre (g, h) and radius 'r' units is given by

(x-g)^2+(y-h)^2=r^2.

Comparing equation (iii) with the above general equation, we get

(g, h) = (2, 6).

So, the centre point is (-5, 7). Hence, the given statement is TRUE.

All the questions are ANSWERED.

Round 736 to nearest ten

Answers

The answer is 740
Because the 6 at the end is higher then 5 therefore we round it up x
740 because 736 the 6 is a high number and anything 5 or higher u round it up

A cell phone company orders 500 new phones from a manufacturer. If the probability of a phone being defective is 2.9%, predict how many of the phones are likely to be defective. Round to the nearest whole number

Answers

About 15 phones are likely to be defective.

Ellie bought two pairs of shoes during a BOGO (Buy One, Get One) sale. She received a 20% discount on the second pair of shoes. The regular price of each pair of shoes was $49.99. How much did Ellie pay for the two pairs of shoes, excluding tax?

Answers

Answer:

89.98

Step-by-step explanation:

49.99 x 20% = 9.998

So, 20% of 49.99 is 10.

49.99 - 10 = 39.99 To get the Total of the discounted item.

49.99 + 39.99 = 89.98 Add final totals to get answer

573,097 rounded to the nearest 100,000

Answers

600,000
_____________

(X+16) (4X-6)

X=

4X=

Answers

Answer:x=0

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