To calculate the volume of 20.0 g of benzene, use the formula volume = mass/density. Given that the density of benzene is 0.879 g/mL, the volume is approximately 22.75 mL when you divide 20.0 g by 0.879 g/mL.
To find the volume of 20.0 g of benzene, we need to use the density of benzene because density is defined as mass per unit volume (density = mass/volume). The formula to calculate the volume from the mass and density is volume = mass/density.
In this case, we are given:
To calculate the volume, we divide the mass by the density:
Volume = Mass / Density = 20.0 g / 0.879 g/mL
We can now perform the calculation:
Volume = 20.0 g / 0.879 g/mL ≈ 22.75 mL
Therefore, the volume of 20.0 g of benzene is approximately 22.75 mL.
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Answer:
(NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(g)
Explanation:
The balanced equation can be written when we know the chemical formula of each reactants and products of the reaction.
Ammonium carbonate = (NH4)2CO3(s)
Ammonia = NH3(g)
carbondioxide = CO2(g)
water = H2O(g)
The ammonium carbonate was decomposed in the reaction , so ,
(NH4)2CO3(s) → NH3(g) + CO2(g) + H2O(g)
The reactant is on the left side while the product is on the right side. Let us balance the equation to make sure every atom of element is same number on both sides of the equation.
(NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(g)
The decomposition of ammonium carbonate upon heating produces ammonia, carbon dioxide, and water. The balanced equation for this decomposition reaction is: (NH4)(HCO3) → NH3 + CO2 + H2O.
The decomposition of solid ammonium carbonate (NH4)(HCO3) upon heating produces ammonia (NH3), carbon dioxide (CO2), and water (H2O) in gas form. This is a specific type of reaction called a decomposition reaction, which breaks down a compound into its constituent parts. The balanced chemical equation informing this process is: (NH4)(HCO3) → NH3 + CO2 + H2O.
Note from this equation, it is clear that the ammonium carbonate completely disappears as it gets converted into gaseous products upon heating.
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Answer:
carbohydrate is an essential biomolecule so the affect of suger fluctuates when enzyme consumes the substrates of glucose molecules
Answer:
Its Carbon Dioxide
Explanation:
I asked the AI
Answer:
61 grams
Explanation:
If the number of moles of CO₂ in the balloon is given to be 3.5 moles, the mass of CO₂ in the balloon will be
number of moles = mass ÷ molar mass
Hence, mass = number of moles × molar mass
Molar mass of CO₂ is 44g. This is 44 because the atomic mass of carbon is 12 while that of oxygen is 16. Thus, 12 + (16 × 2) = 44 g
mass= 3.5 moles × 44g
mass = 154g (which is the initial mass)
When the mass of CO₂ in the 25.5 liter balloon is 154g, the mass of CO₂ in the balloon when the volume of CO₂ in the balloon is 15.4 liter will be X
To get X,
25.5 L ⇒ 154g
15.4 L ⇒ X
cross-multiply, and
X = (15.4 × 154) ÷ 25.5
X = 93.00 grams (which is the final mass)
93.00 grams of CO₂ was left in the balloon, hence the mass of CO₂ that escaped will be: initial mass minus final mass
= 154g - 93g
= 61g
The mass of CO₂ that escaped is 61 grams
Answer: 656 mmHg
Explanation:
Manometers are used to measure the pressure in a container by comparing it to normal atmospheric pressure.
First convert the atmospheric pressure to mmHg
1 torr = 1 mmHg
Therefore, the atmospheric pressure = 742 mmHg
Since the arm connected is higher than the level of the Mercury open to the atmosphere, then the gas pressure is lower than the atmospheric pressure.
Hence,
Pgas = Patm - change in height
Pgas = 742 mmHg - 8.6 cmHg
Balance the unit: 10 mm = 1 cm
Then,
Pgas = 742 mmHg - 86 mmHg
Pgas = 656 mmHg
The gas pressure in the container is 656 mmHg.