Answer:
y = - 3x - 2
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given the equation
6x + 2y = - 4 ( subtract 6x from both sides )
2y = - 6x - 4 ( divide through by 2 )
y = - 3x - 2 ← in slope- intercept form
To put the equation 6x + 2y = -4 into slope-intercept form, subtract 6x from both sides of the equation. Then, divide both sides by 2 to isolate y. The resulting equation is y = -3x - 2.
To put the equation 6x + 2y = -4 into slope-intercept form, we need to solve for y. First, subtract 6x from both sides of the equation: 2y = -6x - 4. Then, divide both sides of the equation by 2 to isolate y: y = -3x - 2. This is now in slope-intercept form, where the slope is -3 and the y-intercept is -2. The question asks to put the equation 6x + 2y = -4 in slope-intercept form and simplify all fractions. Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Here are the steps to follow: Isolate y on one side of the equation: 2y = -6x - 4
Divide all terms by 2 to solve for y: y = -3x - 2
So, the equation in slope-intercept form is y = -3x - 2. The slope (m) is -3 and the y-intercept (b) is -2.
#SPJ11
Answer:
409/252
Step-by-step explanation:
3/4+3/7+ 4/9= 63x3+36x3+28(2^2)/ 2^2x7x3^2
if I am wrong I am sorry
Begin equation . . . 2 times x plus 2 times y equals . . . 4 . . . end equation
A
begin ordered pair, 2, zero, end ordered pair
B
begin ordered pair, zero, 2, end ordered pair
C
begin ordered pair, negative 2, 6, end ordered pair
D
begin ordered pair, 4, negative 2, end ordered pair
Answer: The answer is the Median(D)
Step-by-step explanation:
Answer:
Median
Step-by-step explanation:
Answer:
a) The probability is 0.04
b) The probability is 0.36
c) The pprobability is 0,25
d) The probability is 0.09
Step-by-step explanation:
Lets calculate areas:
the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.
a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04
b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.
c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25
d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.