​​Find the coordinates of the midpoint of with endpoints G(-9, 4) and H(5, 10).

Answers

Answer 1
Answer: ((x_(2) + x_(1))/(2), (y_(2) + y_(1))/(2)) \n((-9 + 5)/(2), (4 + 10)/(2)) \n((-4)/(2), (14)/(2)) \n(-2, 7)

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Please help me with this explain!!!!!

600 divided from 4,800 long division

Answers

It's rather hard to simulate long division through text.

.........  000.125
4800 | 600.000
..........-4800
...........1200.0
............-9600
.............24000
............-24000
.....................0
4800/600= 8

the answer is 8.

Put the following equation of a line into slope-intercept form, simplifying all fractions: 6x + 2y = -4.

Answers

Answer:

y = - 3x - 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given the equation

6x + 2y = - 4 ( subtract 6x from both sides )

2y = - 6x - 4 ( divide through by 2 )

y = - 3x - 2 ← in slope- intercept form

Final answer:

To put the equation 6x + 2y = -4 into slope-intercept form, subtract 6x from both sides of the equation. Then, divide both sides by 2 to isolate y. The resulting equation is y = -3x - 2.

Explanation:

To put the equation 6x + 2y = -4 into slope-intercept form, we need to solve for y. First, subtract 6x from both sides of the equation: 2y = -6x - 4. Then, divide both sides of the equation by 2 to isolate y: y = -3x - 2. This is now in slope-intercept form, where the slope is -3 and the y-intercept is -2. The question asks to put the equation 6x + 2y = -4 in slope-intercept form and simplify all fractions. Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Here are the steps to follow: Isolate y on one side of the equation: 2y = -6x - 4

Divide all terms by 2 to solve for y: y = -3x - 2

So, the equation in slope-intercept form is y = -3x - 2. The slope (m) is -3 and the y-intercept (b) is -2.

Learn more about slope-intercept form here:

brainly.com/question/37778219

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3/4+ 3/7+ 4/9 FRACION HETEROGENEA

Answers

Answer:

409/252

Step-by-step explanation:

3/4+3/7+ 4/9= 63x3+36x3+28(2^2)/ 2^2x7x3^2

if I am wrong I am sorry

Which of the following is the solution to the given system of equations?Begin equation . . . 3 times x plus y equals . . . 6 . . . end equation
Begin equation . . . 2 times x plus 2 times y equals . . . 4 . . . end equation

A
begin ordered pair, 2, zero, end ordered pair

B
begin ordered pair, zero, 2, end ordered pair

C
begin ordered pair, negative 2, 6, end ordered pair

D
begin ordered pair, 4, negative 2, end ordered pair

Answers

It would be A because I think x = 2 and y = 0
The guy on the up is right i check and it is 

begin ordered pair, 2, zero, end ordered pair

Please help I really need it

Answers

Answer: The answer is the Median(D)

Step-by-step explanation:

Answer:

 Median

Step-by-step explanation:

Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates of the outcomes are chosen at random, find the probability that the dart falls (a) within 2 inches of the center. (b) within 2 inches of the rim. (c) within the first quadrant of the target. (d) within the first quadrant and within 2 inches of the rim.

Answers

Answer:

a) The probability is 0.04

b) The probability is 0.36

c) The pprobability is 0,25

d) The probability is 0.09

Step-by-step explanation:

Lets calculate areas:

the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.

a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04

b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.

c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25

d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.