PHYSICS HIGH SCHOOL

Dark spots on the photosphere are known asA. the corona.
B. the chromosphere.
C. sunspots.
D. solar wind.

Answers

Answer 1
Answer: The dark spots that are found on the photosphere are called sunspots. These are a temporary phenomena and are areas of different temperature compared to the surroundings. Sunspots are at a lower temperature compared to the surrpundings and they are created due to magnetic field flux. They can stay on from a few days to a few months and eventually decay.
Answer 2
Answer:

C is the right answer

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An object has a mass of 120 kg on the moon. What is the force of gravity acting on the object on the moon? A. 12.24 N
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D. 196 N User: A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues moving forward at the original speed. This is an example of the effect of
A. velocity.
B. gravity.
C. weight.
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Answers


Well first of all, if the object's mass is 120 kg, then its mass is 120 kg. 
It makes no difference where it happens to be located at the moment. 
Its mass is 120 kg. Period.  It doesn't change.

Weight = (mass) x (acceleration of gravity) .

Acceleration of gravity on the moon is 1.622 m/s² (rounded) .

Weight of the object = (120 kg) x (1.622 m/s²) = 194.6 Newtons.
                                                                   (about 43.8 pounds)

The nearest choice is  D). 196 N.

===========================================

When the bus starts moving forward, the man remains still. 
He leans back, and soon catches up.

When the bus is moving but begins to slow down, the man
continues moving forward at the same speed.  He leans forward,
until the bus stops, and then he eventually stops.

The simplest way to explain this (although it doesn't tell you much)
is to invoke 'inertia'.  'D' is the choice of the choices.
For first question, Gravity is approximately up to 1/6 of Earth's gravity. So object's weight 1200/6=200 N. So answer shall be D.

For second question, intertia is the thing that described in the question. Answer is D.

How does Coulomb's law relate to test charges?

Answers

Coulomb's law relate to test charges whenever the positive charge and the negative charge are placed 1 meters apart inside a vacuum made of air. The force of repulsion between the positive and negative charges are around 9.0x10E9 N.

. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circularpath were reduced, what would happen?

Answers

In this particular case, where car is moving through curvature, so it is moving in circular motion, force acting on car is centripetal force which holds car not to fly out. Centripetal force is always pointed in the middle of circle. Here frictional force has role of centripetal force. If frictional force is to weak, car would fly out of curvutare.

An observer notes that the pitch of a sound is becoming progressively lower. The observer can conclude that the sound is moving

Answers

He can conclude that the source of the sound is moving away from him and that its speed is increasing.
The source of the sound is moving away from the receiver.

Describe what happens if you are riding a skateboard and hit something like a curb with the front wheels.

Answers

If you are riding a skateboard and hit something like a curb with the front wheels then the skateboard would stop due to the friction offered by the club but your body would fall forward due to the effect of that inertia.

What is Newton's first law?

According to Newton's first law, until pushed to alter its condition by the intervention of an external force,

Every object will continue to be at rest or in uniform motion along a single direction until/unless some external force is applied.

When the front wheels of a skateboard collide with something like a curb, then the skateboard will halt because of the friction created by the object, but your body will fall forward as a result of the inertia.

Learn more about Newton's First Law here, refer to the link;

brainly.com/question/1222214

#SPJ2
Your body will keep moving forward and fly off your skateboard since the curb only stops the board, not yourself.

A 1500 kg is being lifted at a constant velocity by a hydralic jack attached to a flat plate. Underneath the plate is a pipe with a top radius of 24 cm which is determined to experienxe a preashre of 81235 N/m^2. The other end of the pipe has a radius of 2.00 cm. How much force must be exterted at this end?

Answers

Answer:

The force that must be exerted at the other end is 102.08 N/m₂

Explanation:

Using Pascal's formula; P₁ = P₂

P₁ = F₁/A₁ = m*g/(πr²)

m = 1500 kg; g = 9.8 m/s², r = 24 cm = 0.24 m

P₁ = (1500 * 9.8)/(22/7 * 0.24 * 0.24)

P₁ = 81235 N/m²

P₂ = F₂/A₂

A₂ = πr² where π = 22/7; r = 2.00 cm = 0.02m

A₂ = 22/7 * 0.02 * 0.02 = 0.00126 m²

P₂  = F₂ / 0.00126 m₂

substituting in the formula  P₁ = P₂

81235 N/m² =  F₂ / 0.00126 m²

F₂ = 81235 N/m² * 0.00126 m²

F₂ = 102.08 N/m₂

Therefore, the force that must be exerted at the other end is 102.08 N/m₂
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