well if you equation is 1/2x=21 then you answer would be x=21
because if you make 1/2 a decimal it is 0.5 and you want to have x alone so you would divide 1/2 by 0.5 and then you would have 1x=21 which is x=21
if f(x+5)=x^2 +kx+30, k= ?
find the smallest zero of f(x+5). x=?
Hope this helps :)
Photo attached.
Answer:
k=13
x= -10
Step-by-step explanation:
f(x)=x²+3x-10
f(x+5)=
=(x+5)(x+5)+3(x+5)-10
=x²+10x+25+3x+15-10
=x²+13x+30
0=x²+13x+30
0=(x+3)(x+10)
x= -3 or -10
-10< -3
smallest zero is -10